1/3 of all the trick or treaters that came to your house were dressed as characters from Star Wars. 3/5 of those
2 answers:
Answer:
1/5
Step-by-step explanation:
Assuming the total number of all the trick or treaters that came to my house is N and the numbers of trick or treaters were dressed as characters from Star Wars is n.
Given that the portion of trick or treaters were dressed as characters from Star Wars, = 1/3 of all the trick or treaters.
Now, 3/5 of those dressed as characters from Star Wars were dressed as the character Darth Vader, so
The number of visitors that were dressed as the character Darth Vader
[ by using equation (i)]
Hence, the fraction of all trick or treaters were dressed as Star Wars and were Darth Vader is 1/5.
You might be interested in
Answer:
The probability that x equals 19.62 is 0
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean and standard deviation
, the z-score of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
In the normal probability distribution, the probability of an exact value, that is, P(X = x) is 0. Thus, the probability that x equals 19.62 is 0
Answer:
The estimated probability that Ginger will eat a a pizza everyday of the week is;
D. 8/10 = 80%
Step-by-step explanation:
The given parameters are;
The frequency with which Ginger buys launch = Everyday
The percentage of the time the cafeteria has pizza out = 80%
The outcome of 0 and 1 = No pizza available
The outcome of 2, 3, 4, 5, 6, 7, 8, and 9 = Pizza available
Therefore, we have the;
Group number Percentage of time pizza available
1 80%
2 80%
3 80%
4 80%
5 40%
6 100%
7 80%
8 100%
9 80%
10 80%
Therefore, the sum of the percentages outcome the days Ginger eats pizza = 0.8 + 0.8 + 0.8 + 0.8 + 0.4 + 1 + 0.8 + 1 + 0.8 + 0.8 = 8
The number of runs of simulation = 10 runs
The estimated probability that Ginger will eat a a pizza everyday of the week = (The sum of the percentages outcome the days Ginger eats pizza)/(The number of runs of simulation)
∴ The estimated probability that Ginger will eat a a pizza everyday of the week = 8/10