The graph of g(x) is the same as that of f(x), EXCEPT that the graph of f(x) has been translated 8 units to the left and 4 units up.
Answer:
-0.3*0.2*12, multiply -0.3 by 0.2 to get -0.06, now multiply 12 by it to get, -0.72.
Step-by-step explanation:
Answer:
Option 2 - Approximately 24–36 pounds
Step-by-step explanation:
Given : A standard American Eskimo dog has a mean weight of 30 pounds with a standard deviation of 2 pounds. Assuming the weights of standard Eskimo dogs are normally distributed.
To find : What range of weights would 99.7% of the dogs have?
Solution :
The range of 99.7% will lie between the mean ± 3 standard deviations.
We have given,
Mean weight of Eskimo dogs is
Standard deviation of Eskimo dogs is
The range of weights would 99.7% of the dogs have,





Therefore, The range is approximately, 24 - 36 pounds.
So, Option 2 is correct.
Answer:
B."5, -3, -4, 1, -1, 6, -4"
Step-by-step explanation:
We are given that
13,5,4,9,7,14,4
We have to find the deviation.
Mean=
Using the formula


Deviation=

13 5
5 -3
4 - 4
9 1
7 -1
14 6
4 - 4
Hence, option B is correct.
Answer:
the correct answer is 4 and 21