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Rzqust [24]
2 years ago
13

Write in slope-intercept form an equation of a line that passes through the point (-2, 7) and m= -4.

Mathematics
1 answer:
Vedmedyk [2.9K]2 years ago
3 0

Answer:

y = -4x - 1

Step-by-step explanation:

We are given the slope and a point.

Point Slope is :

y-y_1=m(x-x_1)

Replace the variables with the appropriate values:

y-y_1=m(x-x_1) \rightarrow\boxed{y-7=-4(x+2)}

Convert to slope-intercept form:

y-7=-4(x+2)\\\\y-7=-4x-8\\\\y-7+7=-4x-8+7\\\\\boxed{y=-4x-1}

Hope this helps!

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Daniella prepares a 1 mg/ml 1 mg/ml myoglobin solution. The molecular weight of myoglobin is 17.8 kDa. 17.8 kDa. Given that the
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Answer:

A = 0.84

Step-by-step explanation:

The absorbance of the myoglobin solution can be calculated by using the Beer-Lambert law:

A = \epsilon*C*l

<u>Where:</u>

<em>A: is the absorbance </em>

<em>ε: is the molar attenuation coefficient = 15,000 M⁻¹cm⁻¹ </em>

<em>l: is the  optical path length = 1 cm</em>

<em>C: is the concentration = 1 mg/ml  </em>

Since the concentration is given in mg/ml and the molar attenuation coefficient is given in M (mol/L) we need to convert the concentration in mg/ml to mol/L and for that, we need to use the molecular weight of myoglobin = 17.8 kDa = 17.8x10³ g/mol:    

C = 1 \frac{mg}{ml} \cdot \frac{1 g}{1000 mg} \cdot \frac{1000 ml}{1 L} \cdot \frac{1 mol}{17.8\cdot 10^{3} g} = 5.62 \cdot 10^{-5} mol/L

Now, we can calculate the absorbance of the myoglobin:

A = 15,000 L*mol^{-1}*cm^{-1}*5.62\cdot 10^{-5} mol*L^{-1}*1 cm = 0.84

Therefore, the absorbance of the myoglobin solution is 0.84.

I hope it helps you!  

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3 years ago
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An event planner is reserving rooms for a company wide event. Each conference room can hold 22 people and 100 people are schedul
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Step-by-step explanation:

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6y-11b+6

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