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3 years ago

1 .-15r+12r 2.-13+16y+5

Mathematics

1 answer:

KengaRu [80]3 years ago

7 0

Agree with that person ^ 1.-15r+12r
2.-13+16y+5

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Find the value of x in the given

Dima020 [189]

Answer:

x = 6.0

Step-by-step explanation:

As the given triangle is a right-angled triangle, we can use the trigonometric ratios to find the required length.

In the given triangle

Hypotenuse = 10

Perpendicular = x

Angle = 37°

As we know the value for perpendicular and hypotenuse, sine will be used.

$sin\ 37 = \frac{Perpendicular}{Hypotenuse}\\sin\ 37 = \frac{x}{10}\\0.6018 = \frac{x}{10}\\x = 0.6018*10\\x = 6.018$

Rounding off to nearest tenth

x = 6.0

Hence,

x = 6.0

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Find the center and the radius of the circle with the equation: x2 - 2x + y2 + 4y + 1 = 0

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Complete the square:

x ^2 - 2x + y ^2 + 4y + 1 = 0

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Find the volume of the solid generated by revolving the region enclosed by the triangle with vertices left parenthesis 4 comma 3

Sedbober [7]

So we have three points A(4,3), B(4,4) and C(7,4).
We introduce a fourth point D(7,3).
We obtain a rectangle ABCD. By rotating the rectangle,
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first cylinder C1 and the inner cylinder with vertices AB by C2.
Computing the volume of C1:
$\pi r^2h=\pi7^2\times1=49\pi$
Computing the volume of the cylinder C2:
$\pi r_2^2h=\pi4^2\times1=16\pi\text{ here the height is 1 again and the radius 4}$
In order to find the volume of the hollow tube, simply compute the difference of the two obtained values like this:
 $49\pi-16\pi=33\pi$
Now, in order to find the volume of the solid generated by revolving the region enclosed by the triangle, simply divide the previous value over two like this:
$\frac{33\pi}{2}$

Answer $\frac{33\pi}{2}$

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