A.all of the above it is correct
Answer:
"Router screening" is the correct option.
Explanation:
- A router that philters packets like a firewall. For certain instances, the whole firewall system is such a single scanning router.
- Often connected to a network stage as well as a container-filter firewall has been the scanning router firewall. This rather firewall operates by filtering protocol characteristics from received packets.
So that the above seems to be the correct approach.
A mathematician because of all their skills they have they suit the job
Answer:
A. 0.0450
B. 4
C. 0.25
D. 37.68
E. 6Hz
F. -0.523
G. 1.5m/s
H. vy = ∂y/∂t = 0.045(-37.68) cos (25.12x - 37.68t - 0.523)
I. -1.67m/s.
Explanation:
Given the equation:
y(x,t) = 0.0450 sin(25.12x - 37.68t-0.523)
Standard wave equation:
y(x, t)=Asin(kx−ωt+ϕ)
a.) Amplitude = 0.0450
b.) Wave number = 1/ λ
λ=2π/k
From the equation k = 25.12
Wavelength(λ ) = 2π/25.12 = 0.25
Wave number (1/0.25) = 4
c.) Wavelength(λ ) = 2π/25.12 = 0.25
d.) Angular frequency(ω)
ωt = 37.68t
ω = 37.68
E.) Frequency (f)
ω = 2πf
f = ω/2π
f = 37.68/6.28
f = 6Hz
f.) Phase angle(ϕ) = -0.523
g.) Wave propagation speed :
ω/k=37.68/25.12=1.5m/s
h.) vy = ∂y/∂t = 0.045(-37.68) cos (25.12x - 37.68t - 0.523)
(i) vy(3.5m, 21s) = 0.045(-37.68) cos (25.12*3.5-37.68*21-0.523) = -1.67m/s.
Answer:
The answer is "supplierType"
Explanation:
Description of the code:
- In the given program two structure is defined, that is "supplierType and paintType", in which "supplierType" structure two-variable name and "supplierID" is defined, that datatype is "String and integer".
- In the next step, "paintType" is declared, in which "supplierType" object supplier is created, in which two string variable "color and paintID" are defined, in which "supplierType" data type is supplied.
