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victus00 [196]
3 years ago
6

I need help pls !!!!!!

Mathematics
1 answer:
swat323 years ago
4 0

\mathfrak{\huge{\pink{\underline{\underline{AnSwEr:-}}}}}

Actually Welcome to the Concept of the Trigonometry.

here, we use the Linear pair property of the adjacent angles.

We know that, all the adjacent angles in a linear pair add to get 180°

so we get as,

=> (n+6) +90°+(2n+3) =180°

=> (n+6) +(2n+3) =180-90

=> 3n+9 = 90

=> 3n= 90-9

=> 3n = 81

hence, n = 81/3

=> n = 27°

thus the value of n is 27° .

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PLEASE HELP I WILL GIVE BRAINLIEST Complete the frequency table: Method of Travel to School Walk/Bike Bus Car Row totals Under a
frozen [14]

Answer:

11%

Step-by-step explanation:

1. Fill out the table with the correct numbers.

2. After you fillout the numbers, you should notice that under the column car and in the first row, there should be the number 18.

3. We know the total number of students under the age of 15 is 165.

4. To find the percent:

       18/165 * 100

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3 years ago
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Pls solve fast ! I’m begging you ! The lesson is operations on functions
Oliga [24]

Step-by-step explanation:

1a. Just add both of them.

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1b. We just subtract both of the functions.

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1c.

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1d.

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2 years ago
Solve for the unknown variable. 144=-12(x+5)
dolphi86 [110]

Answer: x=-17


Step-by-step explanation:

We first distribute the -12 across to the (x+5)

144=-12(x+5)

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Lastly, we divide the equation by -12.

204/-12 = -12x/-12

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3 0
3 years ago
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when a pen is sold at a discount of 15%, there is a gain of Rs 10. but if it is sold at 25% discount, there is a loss of Rs 2. f
LenaWriter [7]

Answer:

Rs 120.  

Step-by-step explanation:

10=0.85SP-CP; CP+10=0.85SP; SP=[CP+10]/0.85 Eq 1. Let SP= Selling Price and CP= Cost Price

-2 =0.75SP-CP; 0.75SP=C-2; SP=[CP-2]/0.75 Eq 2

[CP+10]/0.85=[CP-2]/0.75 : SP of Eq 1=SP of Eq 2

0.75[CP+10]=0.85[CP-2]

0.75CP+7.5=0.85CP-1.7

0.85CP-0.75CP=-1.7–7.5=9.2

0.10CP=9.2; CP=9.2/0.10

CP=Rs 92 Cost Price of pen

10=0.85SP-92; 0.85SP=92+10=102; SP=102/0.85=Rs 120 Marked Price of pen (answer)

From Eq2: -2=0.75SP-CP; 0.75SP=CP-2=92–2=90; SP=90/0.75=Rs120; -2=0.75(120)-CP; CP-2=0.75(120); CP-2=90; CP=90+2=Rs 92

Set CP of Eq 1=CP of Eq 2:

CP=0.85SP-10 from Eq 1; CP=0.75SP+2 from Eq 2;

0.85SP-10=0.75SP+2; 0.85SP-0.75SP=10+2=12

0.10SP=12; SP=12/0.10=Rs120 is the Marked Price(answer)

Normally, the Selling Price is the marked price. The seller will not disclose the Cost Price because it is the price when the item was acquired or procured, otherwise the buyer will ask for more discounts and based his buying price from the Cost Price if it is known. The calculated SP and CP satisfy both Eq 1 and Eq 2. Both Eq 1 and Eq 2 satisfy the given conditions of the problem above.

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