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Kazeer [188]
3 years ago
5

If you have the following equation, 2/3x+5/6-x=2-3/4x what would you multiply each term by to get rid of all the fractions

Mathematics
1 answer:
Genrish500 [490]3 years ago
5 0

Answer:

The answer is 12.

Step-by-step explanation:

You would multiply each of them by 12 to get rid of all of the fractions.

This is because 12 is the least common multiple of the denominators. You can find that by lining up their multiples and looking for the one that is the smallest that they have in common.

3: 3, 6, 9. 12. 15

4: 4. 8. 12. 16, 20

6: 6. 12. 18. 24. 30

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if the ratio of home fans to visiting fans is 5:2 and all 42000 seats in a stadium are filled, how many visiting fans are in att
jeka94

Answer:

12000

Step-by-step explanation:

Sum the parts of the ratio, 5 + 2 = 7

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8 0
3 years ago
Which of the following shows the extraneous solution(s) to the logarithmic equation? log4 (x) + log4(x - 3) = log4 (-7x + 21)
Salsk061 [2.6K]
First join the log4 on the left:

log4( x*(x-3) = log4(-7x+21)

Then x = -7, works: -7*(-10)=70 = -7*(-7)+21

x=-3, 18 = 42, does not work

x=3 0=0 works,

However, when one puts x = -7 in the *original* exression, log4(-7) or log4(-10) do not exist (you know why?). So x= -7 is extraneous.

Now x=3 gives log4(0) on the left and right, which does not exist.

So, C is the answer, both are extraneous. Seem to work but indeed don't work in the *original* equation
 
6 0
3 years ago
Read 2 more answers
SOMEONE HELP PLEASE I DONT WANNA FAIL
r-ruslan [8.4K]

Answer:

A

Step-by-step explanation:

6 0
3 years ago
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