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Rufina [12.5K]
3 years ago
7

Part A: Students from 4 towns attend a conference. Each town is assigned a number from 1 to 4. Drag yes or no next to the first

sentence.
Yes or No

A number is drawn and replaced 6 times. Is this a fair way to pick 6 members to give each town representation? __________

Part B: What is the probability that Town 1 will have at least 1 representative after 6 number draws, to the nearest percent?

probability = __________ %

Mathematics
1 answer:
Nonamiya [84]3 years ago
5 0

Answer:

Part A - No

Part B - 100 %

Step-by-step explanation:

Part A.

This is because, a fair chance requires that each member has the same probability of being picked.

Since there are 4 towns, a fair chance would be 1/4.That is, 1 out of every town.

Part B

The probability of at least 1 representative after 6 number draws is P(at least 1)  = 1 - P(none from Town 1)

P(none from town 1) = 0

P(at least 1)  = 1 - P(none from Town 1)

P(at least 1)  = 1 - 0 = 1

In percentage 1 × 100 % = 100 %

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The answer for 36/4 + 11 \times 8 = 97.

<u>Step-by-step explanation</u>:

The order of operation is done by using BODMAS rule.

B - bracket

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step 1 :

36 divided 4 + 11 \times 8

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step 2 :

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step 3 :

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