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adell [148]
3 years ago
15

The Japanese 5 yen coin has a hole in the middle. If the diameter of the coin is 22 mm and the diameter of the hole is 5 mm, how

would you calculate in terms of how much longer the outer edge is than the inner edge?
Mathematics
3 answers:
Eva8 [605]3 years ago
8 0

Solution:

Given that Japanese 5 yen coin has a hole in the middle. If the diameter of the coin is 22 mm and the diameter of the hole is 5 mm,

So, Our Equation will be 22/5 - 5/2 mm

Let's Solve this Equation ;

☛ 22/5 - 5/2

☛8.5 mm

Therefore, Required Answer is 8. 5 mm .

Ivenika [448]3 years ago
4 0

Answer:

distance = (22/2) - (5/2) = 8.5 mm

Hope this helps chu

Have a great day

☆ Dont forget to mark brainliest ☆

LeTea2 years ago
0 0

Sample response: To find the difference between the outer and inner edges of the coin, you would calculate the circumference of the coin, C= 22π, and the circumference of the hole, C = 5π. Then you would subtract to find the answer, 22π − 5π = 17π.

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3a + 2b, when a = 10 and b= 5
tia_tia [17]

Answer:

40

Step-by-step explanation:

3a + 2b =

3(10) + 2(5)

30 + 10 = 40

I hope this helps!

Have a great day!

8 0
2 years ago
Read 2 more answers
4. A number m is such that when it is divided by 30, 36, and 45 the remainder is always 7,
Bezzdna [24]

Answer:

187

Step-by-step explanation:

A number m is such that when it is divided by 30, 36 and 45 the remainder is always 7.

We should first find the LCM of 30, 36 and 45

We get that the LCM of the three numbers is 280 (working attached).

So now;

\frac{180}{30} = 6

\frac{180}{36} = 5

\frac{180}{45} = 4

But we need a number that leaves a remainder of 7 so we add 7 to 180 to get; 180 + 7 = 187.

5 0
3 years ago
3x-4 or = to 7<br><br><br> plz help
lisabon 2012 [21]

Answer:

3 + 4 = 7  which is true.

Step-by-step explanation:

Whenever you have an equation with a plain variable (that is, no exponent included), there is only one number that will work when substituted for x.

To solve it, you have to "undo" what is done to the variable. You also go in the reverse order of operations, so you do the addition/subtract first, then multiplication/division.

You also have to do the same to both sides, kind of like keeping a balance scale in balance.

In this case, we subtract 4 from both sides first:

3x + 4 -4 = 7 - 4

The + 4 - 4 cancel each other out, so you get:

3x = 3

3x means "3 times x" so you divide by 3 to undo it. I will use the / to indicate division:

3x / 3 = 3 /3  

so 1x = 1.

Since 1x is "1 times x" it is the same as x by itself, so:

x=1

AND, if we substitute 1 back into the original equation (the asterisk stands for multiply):

3 * 1 + 4 = 7

3 * 1 is 3, so:

3 + 4 = 7     which is true.

1 is the only number that works.

Hope this helped.

3 0
2 years ago
Read 2 more answers
In a different plan for area​ codes, the first digit could be any number from 4 through 8​, the second digit was either 3, 4, 5,
Snezhnost [94]

For the first digit, we have 5 options that are 4,5,6,7,8 . For the second digit, we have 4 options which are 3,4,5 or 6 and for the third digit, we have the options of all numbers except 2 or 5 that is 1,3,4,6,7,8,9,0 . SO we have 8 options for third digit . So to find the total number of options, we need to multiply all the possible options for each digit that is 5 times 4 times 8 = 160 . So the number of possible options are 160 .

7 0
3 years ago
A stadium has 45,000 seats. Seats sell for $28 in Section A, $24 in Section B, and $20 in Section C. If section C held 300 fewer
White raven [17]

Answer:

Let's define the variables:

A = number of seats in section A.

B = number of seats in section B.

C = number of seats in section C.

We have the equations:

A + B + C = 45,000.

C - 300 = B/2

A*$28 + B*$24 + C*$20 = $1,139,200

This is a system of equations, the first step to solve this is to isolate one variable in one of the equations, and then replace it in the others.

I will isolate C in the second equation:

C = B/2 + 300.

Now let's replace this in the other two equations:

A + B + B/2 + 300 = 45,000

A*$28 + B*$24 + (B/2 + 300)*$20 = $1,139,200

Let's simplify these equations:

A + B*(3/2) = 44,700

A*$28 + B*$34 + $6,000 = $1,139,200

Now let's isolate A in the first equation:

A = 44,700 - B*(3/2)

Let's replace this in the other equation:

(44,700 - B*(3/2))*$28 + B*$34 + $6,000 = $1,139,200

Now let's solve this for B.

-B*$8 + $1,252,200 = $1,139,200

-B*$8 =  $1,139,200 - $1,252,200  = -$113,000

B = $113,000/8 = 14,125

Now we can replace that in the equations:

A =  44,700 - B*(3/2) =  44,700 - 14,125*(3/2) = 23,512.5, that we should round up to 23,513.

And C = B/2 + 300 = 7362.5

As we rounded the previous one up, we should round this one down to 7362.

3 0
2 years ago
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