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kow [346]
3 years ago
6

Steve has a 100 $ gift card for his phone, he wants to use it on songs a song cost 3.99 how many songs can Steve buy using the g

ift card?
Mathematics
2 answers:
NNADVOKAT [17]3 years ago
8 0

Answer:

<u>Steve</u><u> </u><u>can</u><u> </u><u>buy</u><u> </u><u>2</u><u>5</u><u> </u><u>songs</u><u> </u><u>with</u><u> </u><u>his</u><u> </u><u>gift</u><u> </u><u>card</u><u>.</u>

Step-by-step explanation:

Money with Steve = $ 100

Money per song = $ 3.99

No. of songs Steve can buy =?

No. of songs Steve can buy = Money with Steve ÷ Money per song

No. of songs Steve can buy = $100 ÷ $3.99 (round off 3.99 to 4)

= 100 ÷ 4

= <u>25 songs.</u>

jasenka [17]3 years ago
8 0
100/3.99 = 25.0626566416
Since you can’t buy a card with ¢0626566416 you have to round to 25
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Which of the following have the property that a(x)=a−1(x)? I. y=x II. y=1/x III.y=x^2 IV. y=x^3 A. I and II, only B. IV, only C.
valentina_108 [34]

Answer:

<em>Correct answer:</em>

<em>A. I and II</em>

<em></em>

Step-by-step explanation:

First of all, let us have a look at the steps of finding inverse of a function.

1. Replace y with x and x with y.

2. Solve for y.

3. Replace y with f^{-1}(x)

Given that:

I.\ y=x \\II.\ y=\dfrac{1}x \\III.\ y=x^2 \\IV.\ y=x^3

Now, let us find inverse of each option one by one.

I. y = x, a(x) = x

Replacing y with and x with y:

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x = a^{-1}(x) = a(x)  Hence, I is true.

II. y =\dfrac{1}{x}

Replacing y with and x with y:

x =\dfrac{1}{y}

x=\dfrac{1}{a^{-1}(x)}

\Rightarrow a^{-1}(x) = \dfrac{1}{x}

a^{-1}(x) = a(x)  Hence, II is true.

III. y =x^{2}

Replacing y with and x with y:

x =y^{2}\\\Rightarrow y = \sqrt x\\\Rightarrow a^{-1}(x) = \sqrt{x} \ne a(x)

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Replacing y with and x with y:

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<em>Correct answer:</em>

<em>A. I and II</em>

<em></em>

4 0
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