The program would display "n = 3" as output based on Nya's steps.
<h3>What is a
pseudocode?</h3>
A pseudocode simply refers to a description of the steps contained in an algorithm, especially through the use of a plain (natural) language.
<u>Note:</u> π is equal to 3.14.
Since Nya assigns π, which isn't an integer, the program would determine the integer (n) as follows:
x - 1 < n < x
π - 1 < n < π
Substituting the parameter (3.14) into the formula, we have;
3.14 - 1 < n < 3.14
2.14 < n < 3.14
n = 3.
Read more on pseudocode here: brainly.com/question/13208346
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Answer:
(a) The probability that a single randomly selected value lies between 158.6 and 159.2 is 0.004.
(b) The probability that a sample mean is between 158.6 and 159.2 is 0.0411.
Step-by-step explanation:
Let the random variable <em>X</em> follow a Normal distribution with parameters <em>μ</em> = 155.4 and <em>σ</em> = 49.5.
(a)
Compute the probability that a single randomly selected value lies between 158.6 and 159.2 as follows:
*Use a standard normal table.
Thus, the probability that a single randomly selected value lies between 158.6 and 159.2 is 0.004.
(b)
A sample of <em>n</em> = 246 is selected.
Compute the probability that a sample mean is between 158.6 and 159.2 as follows:
*Use a standard normal table.
Thus, the probability that a sample mean is between 158.6 and 159.2 is 0.0411.
The negative infinity for the x coordinate states that the graph should move to the bottom and the y coordinate is positive infinity so that the graph goes up
the first graph is your answer
19:15 will be the new time
Answer:
Assuming you have the lengths in inches.
Do this: (length in inches * 10) x (length in inches * 10)
Step-by-step explanation:
There's information missing from this question. "The football field is 100 yards long and yards wide", but to find out the area of a rectangle you just need to times the two numbers together.
I assume you have a picture with the lengths in inches on, if you can see how many inches are on the scale drawing, times the inches by 10 for the length in yards for each side. Then times the two lengths (in yards) together for the area.
:)
