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gayaneshka [121]
3 years ago
6

How do you convert 4680 weeks into years? Need answer now please

Mathematics
1 answer:
Serggg [28]3 years ago
6 0
There are 52 weeks in a year... therefore, divide 52 into 4680 :)
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\frac{50}{30}*70=35

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san4es73 [151]
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For 90% confidence interval, \alpha =0.1 and \frac{ \alpha }{2} =0.05

From the chi-square table, the value of \chi^2_{1- \frac{ \alpha }{2} }=\chi^2_{0.95}=35.172 and the value of \chi^2_{ \frac{ \alpha }{2} }=\chi^2_{0.05}=13.091.

The 90% confidence interval for \sigma^2 is given by:

\frac{(n-1)s^2}{\chi^2_{1- \frac{ \alpha }{2} }} \ \textless \ \sigma^2\ \textless \ \frac{(n-1)s^2}{\chi^2_{ \frac{ \alpha }{2} }} \\  \\ = \frac{(24-1)(2.3)^2}{35.172} \ \textless \ \sigma^2\ \textless \ \frac{(24-1)(2.3)^2}{13.091} \\  \\ = \frac{23(5.29)}{35.172} \ \textless \ \sigma^2\ \textless \ \frac{23(5.29)}{13.091} = \frac{121.67}{35.172} \ \textless \ \sigma^2\ \textless \  \frac{121.67}{13.091}  \\  \\ =3.46\ \textless \ \sigma^2\ \textless \ 9.29

And the 90% confidence interval for \sigma is given by:

\sqrt{\frac{(n-1)s^2}{\chi^2_{1- \frac{ \alpha }{2} }}} \ \textless \ \sigma\ \textless \ \sqrt{\frac{(n-1)s^2}{\chi^2_{ \frac{ \alpha }{2} }}} \\  \\ = \sqrt{3.46} \ \textless \ \sigma\ \textless \  \sqrt{9.29} =1.86\ \textless \ \sigma\ \textless \ 3.05
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3 years ago
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gregori [183]

Answer:

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Vlad [161]
Trevor will be saving less.
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Answer:

Step-by-step explanation:

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