Question

Tina, Sijil, Kia, vinayash Alisha and shifa are playing game by forming two teams. Three players in each team how many different ways can they be put into two teams of three players

Answer 1

Answer:

$20$

Step-by-step explanation:

GIVEN: Tina, Sijil, Kia, vinayash Alisha and shifa are playing game by forming two teams Three players in each team.

TO FIND: how many different ways can they be put into two teams of three players.

SOLUTION:

Total number of players $=6$

total teams to be formed $=2$

total players in one team $=3$

we have to number of ways of selecting $3$ players for one team, rest $3$ will go in other team.

Total number of ways of selecting $3$ players $=^6C_3$

                                                                      $=\frac{6!}{3!3!}$

                                                                     $=20$

Hence total number of different ways in which they can be put into two different teams is $6$