Density allows you to find that for the coin to look like gold, the correct answer is: the mass must INCREASE
Density is the relationship between the mass of a body and its volume is constant for solids and liquids.
ρ = m / V
where ρ is the density, m the mass and V the volume of the body
The mass of the coin is
m = ρ V
initially the coin is silver (Ag) with density, ρ_{Ag} = 10.94 g/cm³ and the density of gold (Au) is ρ_{Au} = 19.32 gr/cm³
As the density of gold is greater than the density of silver, we must use some chemical method, for example electroplating, to introduce a small layer of gold or other golden material on the surface, as this layer is very thin, the increase in volume is very small, the mass of the coins is
m₁ = ρ_{Ag] V
m₂ = ρ_{Au} V
where m₁ and m₂ are the masses of the silver and gold coins, respectively
What
ρ_{Au} > ρ_{Ag}
the mass of the coin must increase
With the density we can find that for the peel to look like gold the mass must INCREASE
learn more about density here: brainly.com/question/15164682
I think it would be 0.0025 kg
1) State the balanced chemical equation
Na3 PO4 + 3 AgNO3 → 3NaNO3 + Ag3 PO4
sodium phosphate silver nitrate sodium nitrate silver phosphate
2) State the molar ratios
1 mol Na3PO4 : 3 mol AgNO3 : 3 mol NaNO3 : 1 mol Ag3 PO4
3) As you see 3 moles of Silver Nitrate react with 1 mol of Na3 PO4, then you will need.
The you need to use the molar ratio 1:3 to calculate the number of moles of sodium phosphate
1 mol Ag NO3 * [ 1 mol Na3 PO4 / 3 mol Ag NO3] = 0.33 mol Na3 PO4
Answer: 0.33 mol sodium phosphate
Answer:
I think air is more denser than oxygen
Answer: CuSO4>2-butanol> C4H9OH>C2H6>C3H8
Explanation:
Ionic substances are highly soluble in water. CuSO4 is an ionic salt composed of Cu2+ and SO42- ions. These ions are solvated in water hence the salt easily dissolves in the surrounding water molecules. this accounts for the fact that it is the most soluble of the five substances in water. 2-butanol contains the -OH group which interacts with water by hydrogen bonding. This accounts for the miscibility of alkanols with water in all proportions. however, this solubility in water decreases as the alky backbone increases. hence C4H9OH is less soluble in water that 2-butanol. Alkanes are usually not quite soluble in water but again solubility decreases with increase in the alky backbone hence propane is less soluble in water than ethane.