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4 years ago

How many moles of sodium phosphate would be required to react with 1.0 mol of silver nitrate

1 answer:

3 0

1) State the balanced chemical equation

Na3 PO4 + 3 AgNO3 → 3NaNO3 + Ag3 PO4

sodium phosphate silver nitrate sodium nitrate silver phosphate

2) State the molar ratios

1 mol Na3PO4 : 3 mol AgNO3 : 3 mol NaNO3 : 1 mol Ag3 PO4

3) As you see 3 moles of Silver Nitrate react with 1 mol of Na3 PO4, then you will need.

The you need to use the molar ratio 1:3 to calculate the number of moles of sodium phosphate

1 mol Ag NO3 * [ 1 mol Na3 PO4 / 3 mol Ag NO3] = 0.33 mol Na3 PO4

Answer: 0.33 mol sodium phosphate

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Floods occur when rainfall or snowmelt exceeds the flow capacity of a river. True False

valina [46]

Id say true, as if it exceeds the flow capasity there would be to much water flowing,therefor causing a flood

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3 years ago

When a tip of a plant is cut it doesn't grow well

aleksandr82 [10.1K]

Explanation:

the tip of a growing plant contains special rapidly diving cells called apical meristem ,these cells are responsible for increase in the length of the plant . if we cut out these cells ,length growth of the plant will be stunned as these cells are not present anyplace else.

8 0

3 years ago

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Gallium is produced by the electrolysis of a solution obtained by dissolving gallium oxide in concentrated NaOH(aq). Calculate t

Alina [70]

Answer: The mass of gallium produced by the electrolysis is 0.0354 grams.

Explanation:

The equation for the deposition of Ga(s) from Ga(III) solution follows:

$Ga^{3+}(aq.)+3e^-\rightarrow Ga(s)$

To calculate the total charge, we use the equation:

$C=I\times t$

where,

C = charge

I = current = 0.490 A

t = time required (in seconds) = $50\times 60=300s$ (Conversion factor: 1 min = 60 s)

Putting values in above equation, we get:

$C=0.490\times 300=147C$

To calculate the moles of electrons, we use the equation:

$\text{Moles of electrons}=\frac{C}{F}$

where,

C = charge = 147 C

F = Faradays constant = 96500

$\text{Moles of electrons}=\frac{147}{96500}=1.52\times 10^{-3}mol$

Now, to calculate the moles of gallium, we use the equation:

$\text{Moles of Gallium}=\frac{\text{Moles of electrons}}{n}$

where,

n = number of electrons transferred = 3

Putting values in above equation, we get:

$\text{Moles of Gallium}=\frac{1.52\times 10^{-3}}{3}=5.077\times 10^{-4}mol$

To calculate the mass of gallium, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Moles of Gallium = $5.077\times 10^{-4}mol$

Molar mass of Gallium = 69.72 g/mol

Putting values in above equation, we get:

$5.077\times 10^{-4}mol=\frac{\text{Mass of Gallium}}{69.72g/mol}\\\\\text{Mass of Gallium}=0.0354g$

Hence, the mass of gallium produced by the electrolysis is 0.0354 grams.

8 0

3 years ago

What does chemical reaction describe

Flauer [41]

A chemical reaction (signs)

- rusting
- change in base of chemical
- for example lets say u mix two chemicals, and then it becomes a different new chemical (it changed from the inside)

a physical

- a physical reaction is outer looks not inside.
- it changes on the outside, like changing a color

3 0

3 years ago

Practice Problem: True Stress and Strain A cylindrical specimen of a metal alloy 49.7 mm long and 9.72 mm in diameter is stresse

amm1812

Answer:

The true stress required = 379 MPa

Explanation:

True Stress is the ratio of the internal resistive force to the instantaneous cross-sectional area of the specimen. True Strain is the natural log to the extended length after which load applied to the original length. The cold working stress – strain curve relation is as follows,

σ(t) = K (ε(t))ⁿ, σ(t) is the true stress, ε(t) is the true strain, K is the strength coefficient and n is the strain hardening exponent

True strain is given by

Epsilon t =㏑ (l/l₀)

Substitute㏑(l/l₀) for ε(t)

σ(t) = K(㏑(l/l₀))ⁿ

Given values l₀ = 49.7mm, l =51.7mm , n =0.2 , σ(t) =379Mpa

379 x 10⁶ = K (㏑(51.7/49.7))^0.2

K = 379 x 10⁶/(㏑(51.7/49.7))^0.2

K = 723.48 MPa

Knowing the constant value would be same as the same material is being used in the second test, we can find out the true stress using the above formula replacing the value of the constant.

σ(t) = K(㏑(l/l₀))ⁿ

l₀ = 49.7mm, l = 51.7mm, n = 0.2, K = 723.48Mpa

σ(t) = 723.48 x 106 x (㏑(51.7/49.7))^0.2

σ(t) = 379 MPa

The true stress necessary to plastically elongate the specimen is 379 MPa.

6 0

3 years ago

Read 2 more answers