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masya89 [10]
3 years ago
11

Rank the following substances in order from most soluble in water to least soluble in water: ethane, C2H6; 2-butanol, C4H9OH; co

pper(II) sulfate, CuSO4; and propane, C3H8.
Chemistry
1 answer:
myrzilka [38]3 years ago
6 0

Answer: CuSO4>2-butanol> C4H9OH>C2H6>C3H8

Explanation:

Ionic substances are highly soluble in water. CuSO4 is an ionic salt composed of Cu2+ and SO42- ions. These ions are solvated in water hence the salt easily dissolves in the surrounding water molecules. this accounts for the fact that it is the most soluble of the five substances in water. 2-butanol contains the -OH group which interacts with water by hydrogen bonding. This accounts for the miscibility of alkanols with water in all proportions. however, this solubility in water decreases as the alky backbone increases. hence C4H9OH is less soluble in water that 2-butanol. Alkanes are usually not quite soluble in water but again solubility decreases with increase in the alky backbone hence propane is less soluble in water than ethane.

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A student dissolves 0.0688 mol of sodium hydroxide in water to make a 0.250 L solution. What is the molarity of the solution?
den301095 [7]
Number of moles = 0.0688 moles of NaoH

volume = 0.250 L

Molarity = moles of solute / volume ( L )

M = 0.0688 / 0.250

M = 0.28 M

Answer B
7 0
3 years ago
The ionization energies of Calcium are (in KJ/mol): 1st: 589.8 2nd: 1145.4 3rd: 4912.4
defon

Answer:

See whole explanation to understand

Explanation:

the reason why there is such a large jump from 2nd to 3rd ionization energy for calcium is because to remove the third electron, a larger amount of energy is required, since the shell is closer to the nucleus, and higher attraction exists between them. This is why the second ionization energy is 1125.4 and then the third IE is 4912.4 which is a very big difference. It's all about the elections and energy!!

8 0
3 years ago
Read 2 more answers
An exacuted glass vessel weighs 50 g when empty, 148g when filled with an liquid of density o.989/cc and 50.5 g whenfilled with
Zanzabum

MW of gas : 124.12 g/mol

<h3>Further explanation  </h3>

Density is a quantity derived from the mass and volume  

Density is the ratio of mass per unit volume  

With the same mass, the volume of objects that have a high density will be smaller than objects with a smaller type of density  

The unit of density can be expressed in g/cm³ or kg/m³  

Density formula:  

\large {\boxed {\bold {\rho ~ = ~ \frac {m} {V}}}}

ρ = density  

m = mass  

v = volume  

glass vessel wieight = 50 g

glass vessel + liquid = 148 ⇒ liquid = 148 - 50 =98 g

volume of glass vessel :

\tt V=\dfrac{m}{\rho}=\dfrac{98}{0.989}=99.1~ml

An ideal gas :

m = 50.5 - 50 = 0.5 g

P = 760 mmHg = 1 atm

T = 300 K

\tt PV=\dfrac{mass(m)}{MW}.RT\\\\MW=\dfrac{m.RT}{PV}\\\\Mw=\dfrac{0.5\times 0.082\times 300}{1\times 0.0991}=124.12~g/mol

3 0
3 years ago
The following reactions have the indicated equilibrium constants at a particular temperature: N2(g) + O2(g) ⇌ 2NO(g) Kc = 4.3 ×
Anuta_ua [19.1K]

Answer:

Kc=~1.49x10^3^4}

Explanation:

We have the reactions:

A: N_2_(_g_) + O_2_(_g_)  2NO_(_g_)~~~~~~Kc = 4.3x10^-^2^5

B: 2NO_(_g_)+~O_2_(_g_)~2NO_2_(_g_)~~~Kc = 6.4x10^9

Our <u>target reaction</u> is:

4NO_(_g_)  N_2_(_g_) + 2NO_2_(_g_)

We have NO_(_g_) as a reactive in the target reaction and  NO_(_g_) is present in A reaction but in the products side. So we have to<u> flip reaction A</u>.

A: 2NO_(_g_) N_2_(_g_) + O_2_(_g_) ~Kc =\frac{1}{4.3x10^-^2^5}

Then if we add reactions A and B we can obtain the target reaction, so:

A: 2NO_(_g_) N_2_(_g_) + O_2_(_g_) ~Kc =\frac{1}{4.3x10^-^2^5}

B: 2NO_(_g_)+~O_2_(_g_)~2NO_2_(_g_)~Kc=6.4x10^9

For the <u>final Kc value</u>, we have to keep in mind that when we have to <u>add chemical reactions</u> the total Kc value would be the <u>multiplication</u> of the Kc values in the previous reactions.

4NO_(_g_)  N_2_(_g_) + 2NO_2_(_g_)~~~Kc=\frac{6.4x10^9}{4.3x10^-^2^5}

Kc=~1.49x10^+^3^4}

3 0
3 years ago
Identify this reaction.
MakcuM [25]
<h3>Answer:</h3>

Single displacement reaction

<h3>Explanation:</h3>
  • Single replacement reaction is a type of reaction in which a reactive element displaces a less reactive element from its compound.
  • The reaction given above; Al + H₂SO₄ → Al₂(SO₄)₃ + H₂ is a single replacement reaction.
  • This is because Aluminium takes the place of hydrogen atoms in sulfuric acid to form aluminium sulfate and hydrogen gas.
  • Double replacement reaction is where cations or anions are exchanged between two compounds to form new compounds.
  • For example the reaction; NaCl(aq) + AgNO₃(aq) → NaNO₃(aq) + AgCl(aq) is a double displacement reaction.
6 0
3 years ago
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