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gtnhenbr [62]
3 years ago
6

Which element in period 3 has three times the electronegativity value compared to that of li in period 2

Chemistry
2 answers:
victus00 [196]3 years ago
7 0

Answer:

Nitrogen

Explanation:

Elements in period two includes lithium, beryllium, boron, carbon, nitrogen, oxygen, fluorine and neon.

According to periodic trends, the electro negativity values are expected to increase across the period up to fluorine. Hence, as we go right wards, we encounter elements with higher electronegative values.

While lithium has an electronegative value of 1 , the electronegative value of element nitrogen is thrrr times this which is equal to three

qaws [65]3 years ago
4 0

Answer:

Chlorine(3.16)

Explanation:

The electronegativity of an element is the ability of an atom to attract a bonding pair of an atom. This measures the tendency of an atom to attract electron to itself in a chemical bond  . One of the most electronegative element is fluorine.  

Electronegativity in the periodic table increases from left to right across the period while it decreases down the group in the periodic table.

Lithium is in period 2 with electronegativity of 0.98 . The element in period 3 with electronegativity times 3 of lithium is chlorine . Chlorine has an electronegativity of  3.16.

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If the rate of decrease for the partial pressure of N2H4N2H4 in a closed reaction vessel is 70 torr/htorr/h , what is the rate o
german

Answer:

r_{NH_3}=140torr/h

Explanation:

Hello,

In this case, the undergoing chemical reaction is:

N_2H_4 (g) + H_2 (g) \rightarrow 2 NH_3

Thus, in terms of pressures, the rate becomes:

-r_{N_2H_4}=\frac{1}{2} r_{NH_3}

Thus, the rate of change for the partial pressure of ammonia turns out:

r_{NH_3}=2*(-r_{N_2H_4})\\r_{NH_3}=2*[-(-70torr/h)]\\r_{NH_3}=140torr/h

The rate of decrease of partial pressure of urea is taken negative as it is a reactant whereas ammonia a product which has 2 as its stoichiometric coefficient.

Best regards.

7 0
3 years ago
mickey reacts magnesium with 1.0 M of hydrochloric acid. the reaction tales 2 minutes and 34 seconds to complete. what are 2 way
lutik1710 [3]

Answer:

Explanation:

To slow down this reaction, we can use any of the methods listed below:

  • Increase the size of the magnesium by using solid lumps of  the metal. This will take a much faster time to react than powered and granulated magnesium.
  • Reduce the concentration of the acid.
  • Let the reaction take place at a much lower temperature than that given.

These conditions will slow down a chemical reaction.

7 0
3 years ago
Identify each definition that applies to the compound in red. Check all that apply.
andre [41]

Answer:

Arrhenius acid & Bronsted-Lowry acid

Explanation:

4 0
3 years ago
Does the density of a gas depend on the molar mass of a gas?
amid [387]
No it doesn't. The density of a gas depends on the temperature that is found. If it's hot the density reduces since its molecules spread, while at cold temperatures the density rises.
7 0
3 years ago
If a buffer is composed of 34. 63 ml of 0. 139 m acetic acid and 36. 50 ml of 0. 182 m sodium acetate, how many ml of 0. 100 m h
Neko [114]

The volume is the product of the molar concentration and the moles of the substance. The volume of hydrochloric acid that can be added to the buffer is 0.066 L.

<h3>What is a buffer?</h3>

A buffer is a constant solution with a proton or hydrogen ion concentration with an acid, base, or salt dissolved in them.

The chemical reaction between hydrochloric acid and sodium acetate is given as,

HCl + CH₃Coo-Na → CH₃CooH + NaCl

From above the initials moles of acetic acid are given as,

Moles = molarity × volume

= 0.139 M × 0.0346 L

=  0.0048 moles

The initials moles of sodium acetate are given as,

M = 0.182 M × 0.0365 L

= 0.0066 moles

As it is known that the ratio of the buffer capacity is 10 for sodium acetate and acetic acid so,

Moles sodium acetate ÷ Moles Acetic acid = 10

(0.0066 moles + X) ÷ (0.0048 moles - X)  = 10

Here, X is the moles of HCl and is calculated as,

0.0066 moles + X = 0.048 moles - 10X

11 X = 0.048 ÷ 0.0066

11 X = 7.27

X = 0.66 moles  

The volume of 0.100 HCl with 0.66 moles is:

Volume = moles × molarity

= 0.100 × 0.66

= 0.066 L

Therefore, 0.066 L of 0.100 M HCl is required to reach the buffer capacity.

Learn more about buffer here:

brainly.com/question/24262133

#SPJ4

6 0
1 year ago
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