If T= 101+102+103+...+199 find T
1 answer:
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Answer:
(x,y) = (,
)
Step-by-step explanation:
We have to find point of intersection of two lines.
the given equations of line are:
10x - 4y = 43 - (1)
-3x - 3y = -15 - (2)
Multiplying the first equation by 3 we have:
(10x - 4y = 43)×3 = 30x - 12 y = 129 - (3)
Multiplying second equation by 10 we have :
(-3x - 3y = -15)×10 = -30x -30y = -150 - (4)
Now, adding equation (3) and (4) we have:
-42y = -21
⇒ y =
Now, putting this value of y in equation (1), we have
10x - 2 = 43
⇒ 10x = 45
⇒x =
Hence, the intersection of given two lines is (x,y) = (,
)
Answer:
x = 2 or 3
Step-by-step explanation:
Diagonal of a rhombus bisects the vertex angles. So,
Lets factorise the eqn.
Here x will have 2 values.
1)
2)