If T= 101+102+103+...+199 find T

Please please pleaseeee answer

AVprozaik [17]

Answer:C would be the correct answer

Step-by-step explanation:

3 0

3 years ago

X * X *X*X*X*X*XX hejfsghjjhffvbjjk

Mumz [18]

WHAT DOES THIS MEAN?

5 0

3 years ago

Simplify LaTeX: \Large\frac{-4^{6} \cdot 4^{2}}{4^{4}}

Oksanka [162]

⇨ The value of this <u>simplified expression</u> = -4096/1 or -4096.

To solve this expression, just multiply the power base by how many times indicate the exponent, and then divide the numerator and denominator of the fraction by the same number.

Power or potentiation is a multiplication in equal factors, where there are <em>terms responsible</em> for obtaining the final result. An potency is given by $\large \sf a^{n}.$ The terms of a power are:

Base
Exponent
equal factors
power

✏️ <u>Resolution/Answer</u>:

$\\ \large \sf \dfrac{-4^{6} \cdot 4^{2}}{4^{4}}=\\\\$

Multiply the powers of the numbers at numerator of the fraction, with the base <em>being multiplied by how many times</em> to indicate the exponent.

$\\\large \sf \dfrac{-4^{6} \cdot 4^{2}}{4^{4}}=$

$\large \sf \dfrac{-4\cdot4\cdot4\cdot4\cdot4\cdot4\cdot 4^{2}}{4^{4}}=$

$\large \sf \dfrac{-4\cdot4\cdot4\cdot4\cdot16\cdot 4^{2}}{4^{4}}=$

$\large \sf \dfrac{-4\cdot4\cdot16\cdot16\cdot 4^{2}}{4^{4}}=$

$\large \sf \dfrac{-16\cdot16\cdot16\cdot 4^{2}}{4^{4}}=$

$\large \sf \dfrac{-16\cdot16\cdot16\cdot 4\cdot4}{4^{4}}=$

$\large \sf \dfrac{-16\cdot16\cdot16\cdot 16}{4^{4}}=\\\\$

<em>Multiply </em>the power at denominator of the fraction:

$\\\large \sf \dfrac{-16\cdot16\cdot16\cdot 16}{4^{4}}=$

$\large \sf \dfrac{-16\cdot16\cdot16\cdot 16}{4\cdot4}=$

$\large \sf \dfrac{-16\cdot16\cdot16\cdot 16}{16}=\\\\$

<em>Multiply </em>the numerator numbers together:

$\\\large \sf \dfrac{-16\cdot16\cdot16\cdot 16}{16}=$

$\large \sf \dfrac{-16\cdot16\cdot 256 }{16}=$

$\large \sf \dfrac{-256\cdot 256 }{16}=$

$\large \sf \dfrac{- 65536 }{16}=\\\\$

Simplify the fraction by number 16:

$\\\large \sf \dfrac{- 65536 }{16}=$

$\large \sf \dfrac{- 65536 \div16}{16\div16}=$

${\orange{\boxed{\boxed{\pink {\large \displaystyle \sf { \frac{-4096}{1} \ or \ -4096 }}}}}} \\\\\\$

So this expression in its simplified form = -4096/1 or -4096.

${\orange{\boxed{\boxed{\pink {\large \displaystyle \sf { \frac{-4096}{1} \ or \ -4096 }}}}}}\\\\$

★ Hope this helps! ❤️

6 0

3 years ago

A certain prescription drug diminishes in the system at a rate of 25% per hour. If a person was administered 1450mg of the drug,

Helen [10]

9514 1404 393

Answer:

459 mg
about 20 hours

Step-by-step explanation:

The decay factor is 1 -25% = 0.75 per hour, so the exponential equation can be written ...

r(t) = 1450·0.75^t . . . . . milligrams remaining after t hours

__

a) After 4 hours, the amount remaining is ...

r(4) = 1450·0.75^4 ≈ 458.79 . . . mg

About 459 mg will remain after 4 hours.

__

b) To find the time it takes before the amount remaining is less than 5 mg, we need to solve ...

r(t) < 5

1450·0.75^t < 5 . . . . use the function definition

0.75^t < 5/1450 . . . . divide by 1450

t·log(0.75) < log(1/290) . . . . . take logarithms (reduce fraction)

t > log(1/290)/log(0.75) . . . . . divide by the (negative) coefficient of t

t > 19.708

It will take about 20 hours for the amount of the drug remaining to be less than 5 mg.

7 0

3 years ago

ASAP! NEED HELP!!!<br> ACTUALLY USA TESTPREP BUT STILL. PLEASE HELP!

Rus_ich [418]

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8 0

3 years ago