$\sin ^4 x \tan ^2 x = \dfrac{\sin ^4 x\ \sin ^2 x }{\cos ^2 x} = \dfrac{\sin^6 x}{\cos ^2 x} = \dfrac{(\sin ^2 x)^3}{\cos^2 x}=\dfrac{(1-\cos^2 x)^3}{\cos^2 x}$

7 0

3 years ago

Write the slope-intercept form of the equation of the line that is perpendicular to AB and passes through Point X. Show all work

aleksandr82 [10.1K]

Answer:

Equation of line is y=(12/5)x+2

Step-by-step explanation:

The slope of line AB is -5/12. The line passing X is perpendicular to line AB and hence have a slope of 12/5. The slope intercept form is given by y=mx+c.

Now, point X satisfies the equation. Plugging in the slope of the line we end up with

y=(12/5)*x+c, now to find c

-10=(12/5)*(-5)+c, c=2

Equation of line is y=(12/5)x+2

7 0

3 years ago

What is the equation of the line that is perpendicular to y = -2/3x + 4 and that passes through (–2,–2)?

Rama09 [41]

Answer: y = 3/2x + 1

Step-by-step explanation: For a perpendicular line, take the reciprocal of "m" and reverse the sign.

- 2/3 becomes +3/2

Then substitute the y and x values of the given coordinate into the equation and solve for "b"

y = mx + b

-2 = 3/2(-2) + b

-2 = -3 + b

-2 +3 = b

+1 = b Substitute for b in y = (3/2)x + 1

6 0

3 years ago

Kofi wants to find the most-liked snacks to put in the vending machine at his office so the most people will buy from it.

Whitepunk [10]

Answer:

The correct option is B

Step-by-step explanation:

4 0

3 years ago

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