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jeka94
3 years ago
8

Note: Enter your answer and show all the steps that you use to solve this problem in the space provided

Mathematics
1 answer:
Naddika [18.5K]3 years ago
3 0

Answer:

So if 4% was put into the account every year, then you would have to find 4% of 4,000, which is 160. So 160*3=480. 4,000+480= 4,480 dollars. That is how much would be in the account.

Step-by-step explanation:

Hope that helps

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help it is due today and not links or files of downloads of anything like that just type in your answer plz and thank u :)
pantera1 [17]
The answer should be x=4
4 0
3 years ago
Read 2 more answers
What is the location of the point on the number line that is 3/5 of the way from a=2 to b=17
makkiz [27]

Answer:

11

Step-by-step explanation:

The distance that a is to b is b-a=17-2=15.

The line segment from a=2 to b=17 has length 15.

We need to know what is 3/5 of 15.

3/5 of 15 means what is 3/5 times 15?

(3/5)(15)=3(3)=9

So this means we are looking to make a line segment that is 9 units from 2 which is 2 to 11.

So 11 is 3/5 the way from a=2 to b=17.

Let's check from 2 to 11 that is a length of 9 and from 2 to 17 that is a length of 15.

Is 9/15 equal to 3/5?

Yes, 9/15 can be reduced to 3/5.

4 0
3 years ago
Here are the endpoints of the segments BC, FG, and JK.<br> B, −67
yulyashka [42]

~~~~~~~~~~~~\textit{distance between 2 points} \\\\ B(\stackrel{x_1}{-6}~,~\stackrel{y_1}{7})\qquad C(\stackrel{x_2}{-4}~,~\stackrel{y_2}{4})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ BC=\sqrt{[-4 - (-6)]^2 + [4 - 7]^2}\implies BC=\sqrt{(-4+6)^2+(-3)^2} \\\\\\ BC=\sqrt{2^2+(-3)^2}\implies \boxed{BC=\sqrt{13}} \\\\[-0.35em] ~\dotfill\\\\ ~~~~~~~~~~~~\textit{distance between 2 points}

F(\stackrel{x_1}{-2}~,~\stackrel{y_1}{-4})\qquad G(\stackrel{x_2}{1}~,~\stackrel{y_2}{-2})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ FG=\sqrt{[1 - (-2)]^2 + [-2 - (-4)]^2}\implies FG=\sqrt{(1+2)^2+(-2+4)^2} \\\\\\ FG=\sqrt{9+4}\implies \boxed{FG=\sqrt{13}} \\\\[-0.35em] ~\dotfill\\\\ ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ J(\stackrel{x_1}{4}~,~\stackrel{y_1}{2})\qquad K(\stackrel{x_2}{5}~,~\stackrel{y_2}{-2})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}

JK=\sqrt{[5 - 4]^2 + [-2 - 2]^2}\implies JK=\sqrt{1^2+(-4)^2}\implies \boxed{JK=\sqrt{17}} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \overline{BC}\cong \overline{FG}~\hfill

4 0
1 year ago
Jennifer scores a 77 on her algebra 2 test. The mean on the test was 73. The standard deviation on the test was 5. What was her
MA_775_DIABLO [31]

Answer:

  0.80

Step-by-step explanation:

The z-score is found from the formula ...

  Z = (X -μ)/σ

  Z = (77 -73)/5 = 4/5 = 0.80

Jennifer's Z-score was 0.80.

7 0
3 years ago
On a coordinate plane, the coordinates of vertices R and T for a polygon are R(−6, 2) and T(5, 2). What is the length of Side RT
Rainbow [258]
Use the formula
D=sqrt[ (x2-X1)^2 + (Y2-Y1)^2]

= sqrt(11^2+0^2)=11.

Sqrt means square root.
3 0
2 years ago
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