See the attached figure which represent the rest of the question.
The rest of the question is the attached figure.
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As shown in the attached figure:
(1) ΔMNL is a right triangle at ∠MNL and ∠NML = 58°
∴ ∠L = 180° - (90°+58°) = 32°
(2) ΔQNL is a right triangle at ∠QNL and ∠QLN = 32°
∴ ∠Q = 180° - (90°+32°) = 58°
So, for both of ΔMNL and ΔQNL
1. ∠NLM = ∠ NLQ = 32°
2. ∠Q = ∠M = 58°
3. side NL = side NL
∴ ΔMNL is congruent to ΔQNL by AAS=======OR=======So, for both of ΔMNL and ΔQNL
1. ∠MNL = ∠QNL = 90°
2. side NL = side NL
3. ∠NLM = ∠ NLQ = 32°
∴ ΔMNL is congruent to ΔQNL by ASA=====================================
So, the correct answer is the first option
Yes, they are congruent by either ASA or AAS
Irrational
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You are correct with 80 on that answer. because since it is a polygon all sides add up to 180. you take 180 and subtract the number u have which is 100. u can double check your answer by looking at the angle. by looking its definitely less than 90 and not more than 90. it looks 80 to me and you can prove it by doing this 180-100=80
ANSWER=80°
Answer: A) is the right answer. 
Step-by-step explanation:
Given product : 
To multiply above expression, first we need to combine like terms and then we need to use the law of exponents.
![2.3\times3\times10^{-3}\times10^8\\=(2.3\times3)\times(10^{-3}\times10^8)\\=6.9\times10^{-3+8}......[\text{by law of exponents }a^n\cdot\ a^m=a^{m+n}]\\=6.9\times10^{5}](https://tex.z-dn.net/?f=2.3%5Ctimes3%5Ctimes10%5E%7B-3%7D%5Ctimes10%5E8%5C%5C%3D%282.3%5Ctimes3%29%5Ctimes%2810%5E%7B-3%7D%5Ctimes10%5E8%29%5C%5C%3D6.9%5Ctimes10%5E%7B-3%2B8%7D......%5B%5Ctext%7Bby%20law%20of%20exponents%20%7Da%5En%5Ccdot%5C%20a%5Em%3Da%5E%7Bm%2Bn%7D%5D%5C%5C%3D6.9%5Ctimes10%5E%7B5%7D)
Thus, the answer is
.