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3 years ago

Give the slope-intercept form for the equation. 5x+ 2y = -14

Mathematics

1 answer:

irga5000 [103]3 years ago

5 0

Answer:

$y=-\frac{5}{2} x-7$

Step-by-step explanation:

$5x+2y=-14\\\frac{5x}{2} +\frac{2y}{2} =\frac{-14}{2}$

$\frac{5}{2}x+y=-7$

$y=-\frac{5}{2} x-7$

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You draw 2 cards from a standard 52 card deck without replacing them. what is the probability that both cards are of the same su

Dmitry [639]

As a fraction it would be 13/52
As a percent it would be 25%

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3 years ago

The Rumpart family is building a new room onto their house. The width of the new room will be 16 feet. The length of the room wi

QveST [7]

Answer:

$\text{The length of new room}=16.64\text{ feet}$

$\text{Area of the new room}=266.24\text{ feet}^2$

Step-by-step explanation:

We have been given that the Rumpart family is building a new room onto their house. The width of the new room will be 16 feet.

The length of the room will be 4% greater than the width. This means that length of new room will be 16 feet plus 4% of 16.

$\text{The length of new room}=16+(\frac{4}{100}*16)$

$\text{The length of new room}=16+(0.04*16)$

$\text{The length of new room}=16+0.64$

$\text{The length of new room}=16.64$

Therefore, the expression $16+(0.04*16)$ represents the length of new room and the length of new room is 16.64 feet.

Since we know that area of a rectangular shape is width times length.

$\text{Area of rectangle}=\text{Length*Width}$

$\text{Area of the new room}=16\text{ feet}\times 16.64\text{ feet}$

$\text{Area of the new room}=266.24\text{ feet}^2$

Therefore, the area of the new room will be 266.24 square feet.

5 0

3 years ago

A projectile is launched from the ground at an angle of theta above the horizontal with an initial speed of v in ft/s. The rang

VARVARA [1.3K]

Answer:

$\theta=24.4^\circ$

Step-by-step explanation:

The formula you wrote has the fraction the other way around. You can find that the range of a projectile is in reality approximated by the equation $x=\frac{v^2}{g} sin(2\theta)=\frac{v^2}{32ft/s^2} sin(2\theta)$ , where we will use ft for distances.

From the given equation we have then $\frac{x32ft/s^2}{v^2} =sin(2\theta)$ , which means $\theta=\frac{Arcsin(\frac{x32ft/s^2}{v^2})}{2}$ since the arcsin is the inverse function of the sin.

Since we have x = 170 ft and v = 85 ft/s, we can substitute these values from the equation written, and we will have $\theta=\frac{Arcsin(\frac{(170ft)(32ft/s^2)}{(85ft/s)^2})}{2}$ , and from now on we have just to use a calculator, obtaining $\theta=\frac{Arcsin(0.75294117647)}{2}=\frac{48.84579804^\circ}{2}=24.4^\circ$