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mash [69]
3 years ago
12

Katie wants to collect over 100100100 seashells. She already has 343434 seashells in her collection. Each day, she finds 121212

more seashells on the beach. Katie can use fractions of days to find seashells.
Write an inequality to determine the number of days, ddd, it will take Katie to collect over 100100100 seashells.
Mathematics
2 answers:
Elden [556K]3 years ago
8 0

Katie wants to collect over 100 seashells. She already has 34 seashells in her collection. Each day, she finds 12 more seashells on the beach. Katie can use fractions of days to find seashells.

Write an inequality to determine the number of days, d, it will take Katie to collect over 100 seashells

<em><u>Answer:</u></em>

Kathie needs more than 5 days to get over 100 shells

The required inequality is 34 + 12d > 100

<em><u>Solution:</u></em>

Given that,

Katie wants to collect over 100 seashells.

She already has 34 seashells in her collection.

Each day, she finds 12 more seashells on the beach

Let "d" be the number of days she takes to cover 100 sea shells

From given statement,

She finds 12 seashells each day

Then for "d" days, the number of sea shells she collected is 12d

She already had = 34

So, the equation can be framed as:

34 + 12d > 100

Here we used "greater than" symbol, since she wants to collect over 100 seashells

Solve the inequality

12d >100-34\\\\12d>66\\\\d>\frac{66}{12}\\\\d>5.5

This means she won't have more than  100 shells until the 6th day

Thus she needs more than 5 days to get over 100 shells

larisa [96]3 years ago
8 0

Answer:

34+12d>100

Step-by-step explanation:

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Find the product of all real values of r for which 1/2x=r-x/7
Dahasolnce [82]

Answer:

r = \±\sqrt{14

Product = -14

Step-by-step explanation:

Given

\frac{1}{2x} = \frac{r - x}{7}

Required

Find all product of real values that satisfy the equation

\frac{1}{2x} = \frac{r - x}{7}

Cross multiply:

2x(r - x) = 7 * 1

2xr - 2x^2 = 7

Subtract 7 from both sides

2xr - 2x^2 -7= 7 -7

2xr - 2x^2 -7= 0

Reorder

- 2x^2+ 2xr  -7= 0

Multiply through by -1

2x^2 - 2xr +7= 0

The above represents a quadratic equation and as such could take either of the following conditions.

(1) No real roots:

This possibility does not apply in this case as such, would not be considered.

(2) One real root

This is true if

b^2 - 4ac = 0

For a quadratic equation

ax^2 + bx + c = 0

By comparison with 2x^2 - 2xr +7= 0

a = 2

b = -2r

c =7

Substitute these values in b^2 - 4ac = 0

(-2r)^2 - 4 * 2 * 7 = 0

4r^2 - 56 = 0

Add 56 to both sides

4r^2 - 56 + 56= 0 + 56

4r^2 = 56

Divide through by 4

r^2 = 14

Take square roots

\sqrt{r^2} = \±\sqrt{14

r = \±\sqrt{14

Hence, the possible values of r are:

\sqrt{14 or -\sqrt{14

and the product is:

Product = \sqrt{14} * -\sqrt{14}

Product = -14

8 0
3 years ago
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