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Phoenix [80]
3 years ago
5

A box in a supply room contains 21 compact fluorescent lightbulbs, of which 7 are rated 13-watt, 8 are rated 18-watt, and 6 are

rated 23-watt. Suppose that three of these bulbs are randomly selected. (Round your answers to three decimal places.) (a) What is the probability that exactly two of the selected bulbs are rated 23-watt
Mathematics
1 answer:
RoseWind [281]3 years ago
3 0

Answer:

The probability that exactly two of the selected bulbs are rated 23-watt is:

= 19%

Step-by-step explanation:

Number of fluorescent light bulbs in the box = 21

7/21 = 13-watt rated light bulbs

8/21 = 18-watt rated light bulbs

6/21 = 23-watt rated light bulbs

The probability of selected a 23-watt rated light bulb = 6/21 = 28.57%

Size of random selection of bulbs = 3

The probability that 2 out of these 3 bulbs are 23-watt rated light bulbs is:

= 6/21 * 2/3 = 19%

b) The probability of selecting 2 of the 3 bulbs from exactly the 23-watt rated bulbs is the probability of the 23-watt rated bulbs being selected given the chance of selecting 2/3.

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X+y=3 x=6-4y using substitution
kenny6666 [7]

Givens

x + y = 3

x =6 - 4y

Solution

Use the top equation to substitute for x in the second equation.

x = 3 - y

Put this result into the second given equation and solve for y

3 - y = 6 - 4y        Add 4y to both sides.

3 - y + 4y = 6       Combine on the left

3 + 3y = 6            Subtract 3 from both sides

3 - 3 + 3y = 6 - 3  Combine

3y = 3                   Divide by 3

3y/3 = 3/3             Combine

y = 1                      

=========================

x + y = 3               but y = 1

x + 1 = 3                Subtract 1 from both sides.

x + 1 - 1 =3 - 1

x = 2

Answer

x = 2

y = 1

4 0
3 years ago
Read 2 more answers
Why does cube root 7 equal 7 to the 1/3 power
UNO [17]

Answer:

Step-by-step explanation:

Here's how you convert:

\sqrt[n]{x^m}=x^{\frac{m}{n}  The little number outside the radical, called the index, serves as the denominator in the rational power, and the power on the x inside the radical serves as the numerator in the rational power on the x.

A couple of examples:

\sqrt[3]{x^4}=x^{\frac{4}{3}

\sqrt[5]{x^7}=x^{\frac{7}{5}

It's that simple. For your problem in particular:

\sqrt[3]{7} is the exact same thing as \sqrt[3]{7^1}=7^{\frac{1}{3}

8 0
3 years ago
Find all real and imaginary solutions to the equation x^3-4x^2+x-4=0
lawyer [7]

Step-by-step explanation:

STEP 1

Equation at the end of step 1

(((x3) - 22x2) + x) - 4 = 0

STEP 2

Checking for a perfect cube

2.1 x3-4x2+x-4 is not a perfect cube

<h3>Ans; x=4</h3>
5 0
3 years ago
Write an expression to represent the sum of three consecutive even numbers. Let C represent the first number in the series
Anna [14]
Let, the first number = C
second number will be = C + 2   ['cause next will be odd so we can't include that]
Third number = C + 4

Now, their sum would be:
C + C+2 + C+4 = 3C + 6

In short, Your Answer would be 3C + 6

Hope this helps!


7 0
3 years ago
Read 2 more answers
If -x &lt; -y, then all of the following are true except?
Marysya12 [62]

Answer:

b, c, d are all false

Step-by-step explanation:

Let x=4, y=2. The given statement says ...

... -4 < -2 . . . . . a true statement.

Now, let's look at the answer choices.

... a. -4 < -2 . . . . true

... b. 2(4) < 2(2) . . . . false

... c. 4 +2 < 2 +2 . . . . false

... d. 4/2 < 2/2 . . . . false

Then "a" is true, and "b", "c", and "d" are false.

4 0
3 years ago
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