Givens
x + y = 3
x =6 - 4y
Solution
Use the top equation to substitute for x in the second equation.
x = 3 - y
Put this result into the second given equation and solve for y
3 - y = 6 - 4y Add 4y to both sides.
3 - y + 4y = 6 Combine on the left
3 + 3y = 6 Subtract 3 from both sides
3 - 3 + 3y = 6 - 3 Combine
3y = 3 Divide by 3
3y/3 = 3/3 Combine
y = 1
=========================
x + y = 3 but y = 1
x + 1 = 3 Subtract 1 from both sides.
x + 1 - 1 =3 - 1
x = 2
Answer
x = 2
y = 1
Answer:
Step-by-step explanation:
Here's how you convert:
The little number outside the radical, called the index, serves as the denominator in the rational power, and the power on the x inside the radical serves as the numerator in the rational power on the x.
A couple of examples:
![\sqrt[3]{x^4}=x^{\frac{4}{3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E4%7D%3Dx%5E%7B%5Cfrac%7B4%7D%7B3%7D)
![\sqrt[5]{x^7}=x^{\frac{7}{5}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7Bx%5E7%7D%3Dx%5E%7B%5Cfrac%7B7%7D%7B5%7D)
It's that simple. For your problem in particular:
is the exact same thing as ![\sqrt[3]{7^1}=7^{\frac{1}{3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B7%5E1%7D%3D7%5E%7B%5Cfrac%7B1%7D%7B3%7D)
Step-by-step explanation:
STEP 1
Equation at the end of step 1
(((x3) - 22x2) + x) - 4 = 0
STEP 2
Checking for a perfect cube
2.1 x3-4x2+x-4 is not a perfect cube
<h3>Ans; x=4</h3>
Let, the first number = C
second number will be = C + 2 ['cause next will be odd so we can't include that]
Third number = C + 4
Now, their sum would be:
C + C+2 + C+4 = 3C + 6
In short, Your Answer would be 3C + 6
Hope this helps!
Answer:
b, c, d are all false
Step-by-step explanation:
Let x=4, y=2. The given statement says ...
... -4 < -2 . . . . . a true statement.
Now, let's look at the answer choices.
... a. -4 < -2 . . . . true
... b. 2(4) < 2(2) . . . . false
... c. 4 +2 < 2 +2 . . . . false
... d. 4/2 < 2/2 . . . . false
Then "a" is true, and "b", "c", and "d" are false.