Answer:
The hypothesis is:
<em>H₀</em>:
.
<em>Hₐ</em>:
.
Step-by-step explanation:
Let <em>X</em> = number of men who exercise regularly and <em>Y</em> = number of women who exercise regularly.
The information provided is:
![n_{X}=150\\X=88\\n_{Y}=200\\Y=130](https://tex.z-dn.net/?f=n_%7BX%7D%3D150%5C%5CX%3D88%5C%5Cn_%7BY%7D%3D200%5C%5CY%3D130)
Compute the sample proportion of men and women who exercise regularly as follows:
![\hat p_{X}=\frac{X}{n_{X}}=\frac{88}{150}=0.587](https://tex.z-dn.net/?f=%5Chat%20p_%7BX%7D%3D%5Cfrac%7BX%7D%7Bn_%7BX%7D%7D%3D%5Cfrac%7B88%7D%7B150%7D%3D0.587)
![\hat p_{Y}=\frac{Y}{n_{Y}}=\frac{130}{200}=0.65](https://tex.z-dn.net/?f=%5Chat%20p_%7BY%7D%3D%5Cfrac%7BY%7D%7Bn_%7BY%7D%7D%3D%5Cfrac%7B130%7D%7B200%7D%3D0.65)
The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> = 150 and
.
The random variable <em>Y</em> also follows a Binomial distribution with parameters <em>n</em> = 200 and
.
According to the Central limit theorem, if from an unknown population large samples of sizes <em>n</em> > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.
The mean of this sampling distribution of sample proportion is:
![\hat p=p](https://tex.z-dn.net/?f=%5Chat%20p%3Dp)
The standard deviation of this sampling distribution of sample proportion is:
![\sigma_{\hat p}=\sqrt{\frac{\hat p(1-\hat p)}{n}}](https://tex.z-dn.net/?f=%5Csigma_%7B%5Chat%20p%7D%3D%5Csqrt%7B%5Cfrac%7B%5Chat%20p%281-%5Chat%20p%29%7D%7Bn%7D%7D)
So, the sampling distribution of the proportion of men and women who exercise regularly follows a Normal distribution.
A two proportion <em>z</em>-test cab be performed to determine whether the proportion of women is more than men who exercise regularly.
The hypothesis for this test cab be defined as:
<em>H₀</em>: The proportion of women is same as men who exercise regularly, i.e.
.
<em>Hₐ</em>: The proportion of women is more than men who exercise regularly, i.e.
.