Y-y1= m(x-x1)
y-2= -2(x+6)
y-2= -2x-12
y= -2x-10
Unless there is supposed to be a zero at the end of that 1, then the answer is no
<u>Answer:
</u>
The probability of rolling a number greater than 4 or less than 3 is 
<u>Solution:
</u>
In the given question there are two events as follows:
(a) Rolling a number greater than 4 i.e. A = {5,6}
(b) Rolling a number less than 3 i.e. B = {1,2}
Since a die has 6 numbers,
P(A) =
where P(A) is the probability of occurrence of event A and P(B) = 
Since, Event A and Event B has nothing in common therefore they are mutually exclusive events.
P(A∪B) = P(A) + P(B)



Therefore the probability of getting a number greater than 4 or less than 3 is 
Answer:
3(2-2) * 3(20-2)
3(0) * 3(18)
0 * 54 = 0
Step-by-step explanation:
3(2-2) * 3(20-2)
3(0) * 3(18)
0 * 54 = 0
Answer:
4
Step-by-step explanation:
Nothing else rlly works besides 1,2,4 soo
Kono Dio Da!!!