Answer:
Monosaccharides are simple sugars with a basic formula Cⁿ (H2O)ⁿ. They are classified according to the number of carbon atoms they contain: tetroses (4), pentoses (5) and hexoses (6). There are also mosaccharides with 3 carbon atoms, for example the Dihydroxyacetone.
Explanation:
Monosaccharides have to be aldehydes (-CHO) or ketones (-COO) with more than one alcohol function, which will be located in different carbons.
Answer:
given, mother and father are heterozygotes.
let, father has B blood group and mother has A blood group.
then their heterozygous genotypes are --
father = iB, iO and mother = iA, iO
punnett square will be,
iB iO
iA iA iB iA iO
iO iB iO iO iO
the genotypes of their progeny will be, iAiB , iAiO ,iBiO and iOiO
and phenotypes will be 3 are heterozygous and 1 is homozygous.
Answer: c. Transition Reaction
Explanation:
During the transition reaction, Acetyl-CoA is formed and connects the first stage of glycolysis with the Krebs Cycle (Citric Acid Cycle). In the presence of oxygen, pyruvate enters the mitochondria and is oxidized to form a compound of 2 carbon, acetate, with energy and CO2 release. During this process, the acetate binds to a coenzyme(coenzyme A (CoA)) - forming the acetyl-coenzyme A.
The 3 steps:
1. pyruvate is oxidized and forms acetate with liberation of CO2;
2. the energy released in the oxidation of pyruvate is stored in the reduction reaction of NAD+ to NADH + H+
3. The acetate molecule combines with coenzyme A to form acetyl-coenzyme A.
The answer to this question is :
D. Obstacle Evaluation
