Answer: The enthalpy of reaction is 500.4 kJ/mol
Explanation:
The chemical equation follows:
![16CO_2(g)+18H_2O(g)\rightarrow 2C_8H_18(l)+25O_2(g)](https://tex.z-dn.net/?f=16CO_2%28g%29%2B18H_2O%28g%29%5Crightarrow%202C_8H_18%28l%29%2B25O_2%28g%29)
The equation for the enthalpy change of the above reaction is:
![\Delta H^o_{rxn}=[(2\times \Delta H^o_f_{(C_8H_18(l))})+(25\times \Delta H^o_f_{(O_2(g))})]-[(16\times \Delta H^o_f_{(CO_2(g))})+(18\times \Delta H^o_f_{(H_2O(l))})]](https://tex.z-dn.net/?f=%5CDelta%20H%5Eo_%7Brxn%7D%3D%5B%282%5Ctimes%20%5CDelta%20H%5Eo_f_%7B%28C_8H_18%28l%29%29%7D%29%2B%2825%5Ctimes%20%5CDelta%20H%5Eo_f_%7B%28O_2%28g%29%29%7D%29%5D-%5B%2816%5Ctimes%20%5CDelta%20H%5Eo_f_%7B%28CO_2%28g%29%29%7D%29%2B%2818%5Ctimes%20%5CDelta%20H%5Eo_f_%7B%28H_2O%28l%29%29%7D%29%5D)
![\Delta H^o_f_{(H_2O(g))}=-241.8kJ/mol\\\Delta H^o_f_{(O_2(g))}=0kJ/mol\\\Delta H^o_f_{(CO_2(g))}=-393.5kJ/mol\\\Delta H^o_f_{(C_8H_{18}(l))}=-5074kJ/mol](https://tex.z-dn.net/?f=%5CDelta%20H%5Eo_f_%7B%28H_2O%28g%29%29%7D%3D-241.8kJ%2Fmol%5C%5C%5CDelta%20H%5Eo_f_%7B%28O_2%28g%29%29%7D%3D0kJ%2Fmol%5C%5C%5CDelta%20H%5Eo_f_%7B%28CO_2%28g%29%29%7D%3D-393.5kJ%2Fmol%5C%5C%5CDelta%20H%5Eo_f_%7B%28C_8H_%7B18%7D%28l%29%29%7D%3D-5074kJ%2Fmol)
Putting values in above equation, we get:
![\Delta H^o_{rxn}=[(2\times (-5074))+(25\times (0))]-[(16\times (-393.5))+(18\times (-241.8))]\\\\\Delta H^o_{rxn}=500.4kJ/mol](https://tex.z-dn.net/?f=%5CDelta%20H%5Eo_%7Brxn%7D%3D%5B%282%5Ctimes%20%28-5074%29%29%2B%2825%5Ctimes%20%280%29%29%5D-%5B%2816%5Ctimes%20%28-393.5%29%29%2B%2818%5Ctimes%20%28-241.8%29%29%5D%5C%5C%5C%5C%5CDelta%20H%5Eo_%7Brxn%7D%3D500.4kJ%2Fmol)
The enthalpy of reaction is 500.4 kJ/mol
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The water be disinfected using bleach or what is useable
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