Answer:
The cost of renting the car for 20 days is $481
Step-by-step explanation:
The table of values can be formed as follows;
Day, Cost
1, $44
2, $67
3, $90
4, $113
7, $182
10, $251
From the given values and the scatter plot, there is a straight line relationship between the cost and the number of days of rental of a car.
The line of best fit is therefore a straight line and from the constant increase in cost ($23) for each extra day of rental, it is possible to find the slope, m, of the data as follows;
![Slope, \, m =\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}](https://tex.z-dn.net/?f=Slope%2C%20%5C%2C%20m%20%3D%5Cdfrac%7By_%7B2%7D-y_%7B1%7D%7D%7Bx_%7B2%7D-x_%7B1%7D%7D)
(x₁, y,) and (x₂, y₂) can be taken as (1, $44) and (3, $90) respectively to give;
![Slope, \, m =\dfrac{90-44}{3-1} = \dfrac{46}{2} = 23 \ as \ stated \ above](https://tex.z-dn.net/?f=Slope%2C%20%5C%2C%20m%20%3D%5Cdfrac%7B90-44%7D%7B3-1%7D%20%3D%20%5Cdfrac%7B46%7D%7B2%7D%20%3D%2023%20%5C%20as%20%5C%20stated%20%5C%20above)
The equation in slope and intercept form is therefore, y - 44 = 23×(x - 1), which gives;
y - 44 = 23·x - 23
y = 23·x - 23 + 44 = 23·x + 21
The cost of renting the car for 20 days is then;
10×23 + 21 = $481
The cost of renting the car for 20 days = $481.