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3 years ago

How many solutions does the pair of equations y = 0 and y = -5 have?

Mathematics

1 answer:

Crank3 years ago

8 0

Answer: None

Step-by-step explanation:

y=0 and y=-5 don't have any solutions. When you ask if a pair of equations have a solution, that means there is an intersection of the equations. The 2 equations will meet somewhere, and that is the solution. To find the solution, you set the equations equal to each other.

0≠-5

It is obvious that 0 and -5 are not equal to each other. Therefore, there is no solution. Also, y=0 and y=-5 are horizontal lines that are parallel to each other. They will never meet, which means there will be no intersection. No intersection means no solutions.

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Use the table to write and solve an equation to find the number of

exis [7]

Answer:

$c = 11$

Step-by-step explanation:

Given

$Cars\ Sold:-: 8; 9; 12; c$

Required

What value of c makes the mean = 10

Mean is calculated as

$Mean = \frac{\sum x}{n}$

In this case;

Mean = 10 and n = 4;

So, we have:

$10 = \frac{8+ 9 + 12 + c}{4}$

$10 = \frac{29+ c}{4}$

Multiply both sides by 4

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Solve for c

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3 years ago

If an ant runs randomly through an enclosed

liraira [26]

The area of a circle is π (radius²)

The area of the outer (2-ft) circle is π (2²) = 4 π square feet.

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The inner circle covers 1/4 of the area of the outer circle.

So if the ant wanders around totally aimlessly and randomly, and there's no way to
know where he came from, where he is now, or where he's going next, and there's
an equal chance of him being anywhere in the big circle at any time, then there's a
25% chance of him being inside the small circle at any time, because 1/4 of the
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3 years ago

triangle ABC is Isosceles CA and CB are equal AB is parallels to the x- axis. Work out the coordinate of A. Given that BC=5cm wo

BabaBlast [244]

Answer:

The perimeter of the triangle ABC is 17 cm.

Step-by-step explanation:

Consider the Isosceles triangle ABC.

The sides CA and CB are equal with measures, 5 cm.

The base angles are assumed to be x° each. Hence, the angle ACB is 2x°.

The altitude CP divides the base AB into two equal halves and the angle ACB is also cut into halves.

Consider the right angled triangle ACP.

The sum of all the angles in a triangle is 180°.

Determine the value of x as follows:

x° + x° + 90° = 180°

2x° = 90°

x° = 45°

Compute the length of side AP as follows:

$cos\ 45^{0}=\frac{AP}{CA}$

$\frac{1}{\sqrt{2}}=\frac{AP}{5}$

$AP =\frac{5}{\sqrt{2}}\\\\AP=3.5$

Then the length of side AB is:

AB = AP + PB

= 3.5 + 3.5

= 7 cm

The perimeter of triangle ABC is:

Perimeter = AB + CA + CB

= 7 + 5 + 5

= 17

Thus, the perimeter of the triangle ABC is 17 cm.

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3 years ago

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DENIUS [597]

Answer:

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Step-by-step explanation:

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Marta_Voda [28]

Answer:

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Step-by-step explanation:

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