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3 years ago

HURRY PLEASE

Mathematics

2 answers:

Brrunno [24]3 years ago

8 0

Answer:

$x=5$

Step-by-step explanation:

$6x-7=2x+13$

$6x-7+7=2x+13+7$

$6x=2x+20$

$6x-2x=2x+20-2x$

$4x=20$

$\frac{4x}{4}=\frac{20}{4}$

$x=5$

Hope this helps!!

All the love, Ya boi Fraser :)

docker41 [41]3 years ago

4 0

The answer is x=5
• you have to collect like terms
• put the like terms on one side of the equation then calculate
• then you divide it and you get your answer
6x -7=2x +13
6x - 2x= 13 + 7
4x = 20
X= 20\4
x=5

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Guys I need help plz and can you show work also thx

Helen [10]

Answer: first problem 3rd choice The graph shifts vertically up 5 units

11.) the y intercept is -5

19.) f(-8) = -18

last item third choice All real numbers such that are ≥ 0 and ≤ 40

Step-by-step explanation:

19.) f(x)=2(-8 -3) + 4

2 (-11) + 4

-22 + 4

f(-8) = -18

4 0

3 years ago

KM bisects ÐJKL, mÐJKM = (2x + 5)°, and mÐMKL = (5x – 10)°. Find mÐJKM.

Gnom [1K]

Answer:

15 °

Step-by-step explanation:

An angular bisector can divide the angle in to 2 congruent angles.

According to the question, the angular bisector KM divides J K L angle into 2 congruent angles.

So,

< J K M = < M K L

2x + 5 = 5x - 10

Now let us find the value of x.

2x + 5 = 5x - 10

2x + 5 + 10 = 5x

15 = 5x - 2x

15 = 3x

You can divide both sides by 3.

5 = x

According to the question, we are asked to find the < J K M.

So,

< J K M = 2x + 5

= 2 × 5 + 5

= 10 + 5

= 15

Hope this helps :-)

4 0

3 years ago

What is the equation of a line with a y-intercept at (0, 2) and a slope of 3? a. y = 2 x + 3 c. y = 3 x + 2 b. y = 3 x minus 2 d

lukranit [14]

Answer:

C) y = 3x + 2

Step-by-step explanation:

Given the slope of the line, m = 3, and the coordinates of the y-intercept, (0, 2).

We can substitute these values into the following slope-intercept form, y = mx + b, where:

m = slope

b = the y-coordinate of the y-intercept.

Therefore, the correct answer is option C, where it shows the equation of the line in slope-intercept form is: y = 3x + 2.

3 0

3 years ago

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ddd [48]

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4 0

3 years ago

suppose we want to choose 6 letters without replacement from 13 distinct letters. A) how many ways can this be done if order doe

kiruha [24]

Answer: A) 1716 B) 1235520

Step-by-step explanation:

If order doesn't matter , then we use combinations, where the number of combinations of selecting r things from n is given by :-

$^nC_r=\dfrac{n!}{r!(n-r)!}$

If order matters , then we use permutations, where the number of permutations of selecting r things from n is given by :-

$^nP_r=\dfrac{n!}{(n-r)!}$

Given, Total distinct letters = 13

To choose = 6 letters

A) Number of ways to choose (if order does not matter)= $^{13}C_6$

$=\dfrac{13!}{6!7!}=\dfrac{13\times12\times11\times10\times9\times8\times7!}{(720)\times 7!}\\\\= $$1716$

B) Number of ways to choose (if order matters)= $^{13}P_6$

$=\dfrac{13!}{7!}=\dfrac{13\times12\times11\times10\times9\times8\times7!} 7!}\\\\= $$1235520$

Hence, A) 1716 B) 1235520

5 0

4 years ago