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3 years ago

Here is a question for you

Mathematics

1 answer:

VARVARA [1.3K]3 years ago

3 0

Answer: That looks so hard

Step-by-step explanation:

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The table below shows the height (in inches) and weight (in pounds) of eight basketball players.

Eduardwww [97]

Hello,
Please, see the attached file.
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4 0

3 years ago

Solve the following equation for G:2 (g-h) = b+4

Klio2033 [76]

If the equation 2(g - h) = b + 4 is solved for g. Then the value of g will be b/2 + h + 2.

<h3>What is the solution of the equation?</h3>

A combination of equations solution is a collection of values x, y, z, etc. that enable all of the calculations to true at the same time.

The equation is given below.

2(g - h) = b + 4

Then solve the equation for the value of g. Then we have

2(g - h) = b + 4

g - h = b/2 + 2

g = h + b/2 + 2

More about the solution of the equation link is given below.

brainly.com/question/545403

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2 years ago

Convert 9/20 into a decimal using long division

Mice21 [21]

Answer:

0.45

Step-by-step explanation:

8 0

3 years ago

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What is 147,591 rounded to the nearest ten

Basile [38]

Answer:

147,590

Step-by-step explanation:

b/c the 90's are in the tens and 5 or more add one more, so since it's less than five, you round down. So the answer would be 147,590

4 0

3 years ago

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Hello people ~

Luden [163]

Cone details:

height: h cm

radius: r cm

Sphere details:

radius: 10 cm

================

From the endpoints (EO, UO) of the circle to the center of the circle (O), the radius is will be always the same.

Using Pythagoras Theorem

(a)

TO² + TU² = OU²

(h-10)² + r² = 10² [insert values]

r² = 10² - (h-10)² [change sides]

r² = 100 - (h² -20h + 100) [expand]

r² = 100 - h² + 20h -100 [simplify]

r² = 20h - h² [shown]

r = √20h - h² ["r" in terms of "h"]

(b)

volume of cone = 1/3 * π * r² * h

===========================

$\longrightarrow \sf V = \dfrac{1}{3} * \pi * (\sqrt{20h - h^2})^2 \ ( h)$

$\longrightarrow \sf V = \dfrac{1}{3} * \pi * (20h - h^2) (h)$

$\longrightarrow \sf V = \dfrac{1}{3} * \pi * (20 - h) (h) ( h)$

$\longrightarrow \sf V = \dfrac{1}{3} \pi h^2(20-h)$

To find maximum/minimum, we have to find first derivative.

(c)

First derivative

$\Longrightarrow \sf V' =\dfrac{d}{dx} ( \dfrac{1}{3} \pi h^2(20-h) )$

apply chain rule

$\sf \Longrightarrow V'=\dfrac{\pi \left(40h-3h^2\right)}{3}$

Equate the first derivative to zero, that is V'(x) = 0

$\Longrightarrow \sf \dfrac{\pi \left(40h-3h^2\right)}{3}=0$

$\Longrightarrow \sf 40h-3h^2=0$

$\Longrightarrow \sf h(40-3h)=0$

$\Longrightarrow \sf h=0, \ 40-3h=0$

$\Longrightarrow \sf h=0,\:h=\dfrac{40}{3}$

maximum volume: when h = 40/3

$\sf \Longrightarrow max= \dfrac{1}{3} \pi (\dfrac{40}{3} )^2(20-\dfrac{40}{3} )$

$\sf \Longrightarrow maximum= 1241.123 \ cm^3$

minimum volume: when h = 0

$\sf \Longrightarrow min= \dfrac{1}{3} \pi (0)^2(20-0)$

$\sf \Longrightarrow minimum=0 \ cm^3$

6 0

2 years ago

Read 2 more answers