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PtichkaEL [24]
3 years ago
13

Here is a question for you

Mathematics
1 answer:
VARVARA [1.3K]3 years ago
3 0

Answer: That looks so hard

Step-by-step explanation:

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Hello,
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Solve the following equation for <br><br><br> G:2 (g-h) = b+4
Klio2033 [76]

If the equation 2(g - h) = b + 4 is solved for g. Then the value of g will be b/2 + h + 2.

<h3>What is the solution of the equation?</h3>

A combination of equations solution is a collection of values x, y, z, etc. that enable all of the calculations to true at the same time.

The equation is given below.

2(g - h) = b + 4

Then solve the equation for the value of g. Then we have

2(g - h) = b + 4

   g - h = b/2 + 2

        g = h + b/2 + 2

More about the solution of the equation link is given below.

brainly.com/question/545403

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3 0
2 years ago
Convert 9/20 into a decimal using long division
Mice21 [21]

Answer:

0.45

Step-by-step explanation:

8 0
3 years ago
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What is 147,591 rounded to the nearest ten
Basile [38]

Answer:

147,590

Step-by-step explanation:

b/c the 90's are in the tens and 5 or more add one more, so since it's less than five, you round down. So the answer would be 147,590

4 0
3 years ago
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Hello people ~
Luden [163]

Cone details:

  • height: h cm
  • radius: r cm

Sphere details:

  • radius: 10 cm

================

From the endpoints (EO, UO) of the circle to the center of the circle (O), the radius is will be always the same.

<u>Using Pythagoras Theorem</u>

(a)

TO² + TU² = OU²

(h-10)² + r² = 10²                                   [insert values]

r² = 10² - (h-10)²                                     [change sides]

r² = 100 - (h² -20h + 100)                       [expand]

r² = 100 - h² + 20h -100                        [simplify]

r² = 20h - h²                                          [shown]

r = √20h - h²                                       ["r" in terms of "h"]

(b)

volume of cone = 1/3 * π * r² * h

===========================

\longrightarrow \sf V = \dfrac{1}{3}  * \pi  * (\sqrt{20h - h^2})^2  \  ( h)

\longrightarrow \sf V = \dfrac{1}{3}  * \pi  * (20h - h^2)  (h)

\longrightarrow \sf V = \dfrac{1}{3}  * \pi  * (20 - h) (h) ( h)

\longrightarrow \sf V = \dfrac{1}{3} \pi h^2(20-h)

To find maximum/minimum, we have to find first derivative.

(c)

<u>First derivative</u>

\Longrightarrow \sf V' =\dfrac{d}{dx} ( \dfrac{1}{3} \pi h^2(20-h) )

<u>apply chain rule</u>

\sf \Longrightarrow V'=\dfrac{\pi \left(40h-3h^2\right)}{3}

<u>Equate the first derivative to zero, that is V'(x) = 0</u>

\Longrightarrow \sf \dfrac{\pi \left(40h-3h^2\right)}{3}=0

\Longrightarrow \sf 40h-3h^2=0

\Longrightarrow \sf h(40-3h)=0

\Longrightarrow \sf h=0, \ 40-3h=0

\Longrightarrow \sf  h=0,\:h=\dfrac{40}{3}<u />

<u>maximum volume:</u>                <u>when h = 40/3</u>

\sf \Longrightarrow max=  \dfrac{1}{3} \pi (\dfrac{40}{3} )^2(20-\dfrac{40}{3} )

\sf \Longrightarrow maximum= 1241.123 \ cm^3

<u>minimum volume:</u>                 <u>when h = 0</u>

\sf \Longrightarrow min=  \dfrac{1}{3} \pi (0)^2(20-0)

\sf \Longrightarrow minimum=0 \ cm^3

6 0
2 years ago
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