Answer:
the impact on the water varies from different heights, therefore the mass stays the same, yet the force on the water increases from a higher height. A taller height will produce a bigger splash!
Explanation:
Answer:
A) i) Dynamic error ≈ 3.1%
ii) phase shift ≈ -12°
B) 79971.89 rad/s
Explanation:
Given data :
Damping ratio = 0.5
natural frequency = 18,000 Hz
<u>a) Calculate the dynamic error and phase shift in accelerometer output at an impart vibration of 4500 Hz</u>
i) Dynamic error
This can be calculated using magnitude ratio formula attached below is the solution
dynamic error ≈ 3.1%
ii) phase shift
This phase shift can be calculated using frequency dependent phase shift formula
phase shift ≈ -12°
<u>B) Determine resonance frequency </u>
Wr = 2
( 18000
) = 79971.89 rad/s
C) The maximum magnitude ratio that the system can achieve
Answer:
8.1345°
Explanation:
We apply
to the wire to obtain:

#The magnitude of the magnetic force acting on the wire is given by:

#Substitute for
to obtain:

Solve for
:
![\theta=sin^{-1}[\frac{IlB}{mg}]](https://tex.z-dn.net/?f=%5Ctheta%3Dsin%5E%7B-1%7D%5B%5Cfrac%7BIlB%7D%7Bmg%7D%5D)
We the substitute the numerical values to calculate the equilibrium angular displacement:
![\theta= sin^{-1}[\frac{0.2A\times0.52m\times 0.040T}{0.003\ kg\times9.8m/s^2}]\\\\=8.1345\textdegree](https://tex.z-dn.net/?f=%5Ctheta%3D%20sin%5E%7B-1%7D%5B%5Cfrac%7B0.2A%5Ctimes0.52m%5Ctimes%200.040T%7D%7B0.003%5C%20kg%5Ctimes9.8m%2Fs%5E2%7D%5D%5C%5C%5C%5C%3D8.1345%5Ctextdegree)
Hence, the equilibrium angular displacement of the wire from vertical if the horizontal magnetic field is 8.1345°
The answer I think is C -7.6 m/s
Answer:
A. They have the same number of valence electrons
Explanation: