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Serggg [28]
3 years ago
14

Mary is 52kgs and standing on a ladder. What forces are acting on her?

Physics
1 answer:
Rus_ich [418]3 years ago
8 0

Answer:

3 forces are acting on her: Friction, Gravity and Muscular force.

Explanation:

Due to gravity and friction she is remaining on the ladder without flying and by not slipping.

Because of muscular force she is being able to interact with ladder and stand on it. Otherwise she will fell down.

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Which describes freefall
Sati [7]
A motion where gravity is the only force acting upon it
6 0
3 years ago
How are energy, force, and the motion of objects related?
OLEGan [10]

Answer:

When two objects interact, each one exerts a force on the other that can cause energy to be transferred to or from the object. For example, when energy is transferred to an Earth-object system as an object is raised, the gravitational field energy of the system increases. This energy is released as the object falls; the mechanism of this release is the gravitational force. Likewise, two magnetic and electrically charged objects interacting at a distance exert forces on each other that can transfer energy between the interacting objects.

Explanation:

Even when an object is sitting still, it has energy stored inside that can be turned into kinetic energy (motion). ... A force is a push or pull that causes an object to move, change direction, change speed, or stop. Without a force, an object that is moving will continue to move and an object at rest will remain at rest.

5 0
3 years ago
Read 2 more answers
A hockey puck has a coefficient of kinetic friction of μk = .35. If the puck feels a normal force (FN) of 5 N, what is the frict
alina1380 [7]

Answer:

The frictional force is  F_f =  1.75 \  N

Explanation:

From the question we are told that

     The coefficient of kinetic force is  μk = 0.35

     The normal force felt by the puck is  F_N  =  5 \  N

Generally the frictional force that acts on the puck is mathematically represented as

          F_f =  \mu_k  *  F_N

=>       F_f =  0.35  *  5

=>       F_f =  1.75 \  N

3 0
3 years ago
A body of mass 25kg, moving at 3 ms per second on a rough horizontal floor brought to rest after sliding through a distance of 2
erastova [34]
You have to solve this by using the equations of motion:
u=3
v=0
s=2.5
a=?
v^2=u^2+2as
0=9+5s
Giving a=-1.8m/s^2

Then using the equation:
F=ma
F is the frictional force as there is no other force acting and its negative as its in the opposite direction to the direction of motion.

-F=25(-1.8)
F=45N

Then use the formula:
F=uR
Where u is the coefficient of friction, R is the normal force and F is the frictional force.

45=u(25g)
45=u(25*10)

Therefore, the coefficient of friction is 0.18

Hope that helps




5 0
3 years ago
What happens when tectonic plates move away from each other? Molten matter cools and sinks towards the core. Lava travels away f
satela [25.4K]
Molten Mattet Seeps through the crust and forms new land.
8 0
3 years ago
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