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alina1380 [7]
3 years ago
15

30 POINTS!!!Need help!!! A charge of 8.5 × 10–6 C is in an electric field that has a strength of 3.2 × 105 N/C. What is the elec

tric force acting on the charge? A. 0.27 N B. 2.7 N C. 27 N D. 270 N
Physics
2 answers:
REY [17]3 years ago
6 0

Explanation :

It is given that,

Charge, q=8.5\times 10^{-6}\ C

The electric field acting on the charge, E=3.2\times 10^{5}\ N/C

The relation between the electric field and the electric charge is given by :

F = q E

F=8.5\times 10^{-6}\ C\times  3.2\times 10^{5}\ N/C

F = 2.72 N

So, the correct option is (B) 2.7 N

Hence, this is the required solution.

son4ous [18]3 years ago
4 0

your correct its b on edge

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Initial P.E+Initial K.E=Final P.E+Final K.E

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\frac{v^24}{L^2}=\frac{6g}{L}

v^2=\frac{6g\times L^2}{4L}

v^2=\frac{3gL}{2}

v=\sqrt{\frac{3}{2}gL}

Hence, the speed of its center of mass =\sqrt{\frac{3}{2}gL}

4 0
4 years ago
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anyanavicka [17]

Answer:

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The function is s=4.725895t^2

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3 years ago
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