GIVING BRAINLIEST PLEASE HELP!!
2 answers:
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Answer:
16,126 ft
Step-by-step explanation:
Using the net change theorem and letting s(t) represent the aircraft's position, and s(0) be the aircraft's position at time t = 0, s(0) = 15000 ft and s(15 be the aircraft's position at time, t = 15 minutes respectively, then,
s(15) - s(0) = ∫₀¹⁵f(t)dt
s(15) - s(0) = ∫₀¹⁵[]dt
s(15) - 15000 = []₀¹⁵
s(15) - 15,000 ft =
s(15) = 15,000 ft + 1126.07 ft
s(15) = 16,126.07 ft
s(15) ≅ 16,126 ft to the nearest foot