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2 years ago

The 400-meter race times at a state track meet are normally distributed with a mean

Mathematics

1 answer:

rjkz [21]2 years ago

8 0

Answer:

P = 1.214

Step-by-step explanation:

Draw a normal probability curve.

Find the z score which comes out to be 0.18 (0.181578947)

look for the probability in the table.

look across 0.1 and under 8.

Get the probability and add 0.5 to it

so rhats:

0.714 + 0.5 = 1.214

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Blake is a songwriter who collects royalties on his songs whenever they are played in a commercial or a movie. Blake will earn $

Mrac [35]

Answer:

It was played in 3 movies and in 10 commercials.

Step-by-step explanation:

110 times 3 = 330

530 minus 330 = 200

200 divided by 20 = 10

3 0

2 years ago

Simplify (11+4)x10+5

AURORKA [14]

Answer:

155

Step-by-step explanation:

= (15)x10+5

= 150+5

= 155

4 0

3 years ago

Read 2 more answers

2. A hemispherical water tank with a volume of 2094 m will have a radius of which

Ivahew [28]

2.5 m jsjwnejdogondbsjsofj find

3 0

2 years ago

Helpppp a girl outtt i will give brainlest

Ivenika [448]

Answer:

Y= 40

Step-by-step explanation:

I know the y equals 40 because I used

$a {}^{2} + b {}^{2} = c {}^{2}$

But for z and x I got stuck, so I hope I helped you a little to move forward with this problem.

YOU CAN DO THIS!!!!!

7 0

2 years ago

Suppose you choose a team of two people from a group of n > 1 people, and your opponent does the same (your choices are allow

jonny [76]

Answer:

The number of possible choices of my team and the opponents team is

$\left\begin{array}{ccc}n-1\\E\\n=1\end{array}\right i^{3}$

Step-by-step explanation:

selecting the first team from n people we have $\left(\begin{array}{ccc}n\\1\\\end{array}\right) = n$ possibility and choosing second team from the rest of n-1 people we have $\left(\begin{array}{ccc}n-1\\1\\\end{array}\right) = n-1$

As { A, B} = {B , A}

Therefore, the total possibility is $\frac{n(n-1)}{2}$

Since our choices are allowed to overlap, the second team is $\frac{n(n-1)}{2}$

Possibility of choosing both teams will be

$\frac{n(n-1)}{2} * \frac{n(n-1)}{2} \\\\= [\frac{n(n-1)}{2}] ^{2}$

We now have the formula

1³ + 2³ + ........... + n³ = $[\frac{n(n+1)}{2}] ^{2}$

1³ + 2³ + ............ + (n-1)³ = $[x^{2} \frac{n(n-1)}{2}] ^{2}$

= $\left[\begin{array}{ccc}n-1\\E\\i=1\end{array}\right] = [\frac{n(n-1)}{2}]^{3}$

4 0

3 years ago