Nickel (Ni) has the charge as +3 while oxygen (O) has -2. Hence, the chemical formula for the nickel (iii) oxide is Ni₂O₃.
molar mass of Ni = 58.69 g/mol
molar mass of O = <span>15.99 g/mol
number of Ni atoms in </span>Ni₂O₃ = 2
Molar mass of Ni in Ni₂O₃ = 2 x 58.69 g/mol = 117.38 g/mol
number of O atoms in Ni₂O₃ = 3
Molar mass of O in Ni₂O₃ = 3 x 15.99 g/mol = 47.97 g/mol
Hence, molar mass of compound = 117.38 g/mol + 47.97 g/mol
= 165.35 g/mol
=<span> 165.4 g/mol</span>
look at the chemical tables. but i believe it is A
Ra(s) + H₂O(g) → Ra(OH)₂ (aq) + H₂ (g)
<u>Explanation:</u>
Radioactive radium reacts easily with water produces radium hydroxide and hydrogen gas. In this reaction, Radium is sin solid state reacts with the water in the gaseous state to produces aqueous radium hydroxide and the hydrogen gas. This reaction occurs rapidly than in Barium. We can write this reaction as,
Radium(s) + water(g) → Radium hydroxide (aq) + Hydrogen (gas)
This can be represented using the symbols as,
Ra(s) + H₂O(g) → Ra(OH)₂ (aq) + H₂ (g)
Thus the above process can be expressed with such chemical reaction.
Answer: the answer is b: sp3d
Explanation: BrF3 has a Bent T shaped structure with Br as a central atom bonded with three F atoms (three bond pairs) and two lone pairs. Hence , the hybridization would be sp3d. Br atom has 7 electron in its outer most shell. After the bond formation of BrF3 molecule we have 3 bond pairs+ 2 lone pairs
The answer of the question is 9075
