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Pepsi [2]
3 years ago
8

How do you balance the chemical equation CH4+ O2= CO2+ 4H2O

Chemistry
2 answers:
viva [34]3 years ago
7 0

CH4+O2=CO2+4H20

now split the equation in half

CH4+O2                 I                  CO2 + 4H2O

C = 1                      I                  C = 1                    

H = 4                      I                  H = 8

O = 2                      I                 O = 3


CH4+ 2O2 = CO2 + 2H20

prohojiy [21]3 years ago
5 0

Answer:

\huge \boxed{\mathrm{CH_4+ 2O_2 \Rightarrow CO_2 +2 H_2O}}

\rule[225]{225}{2}

Explanation:

\sf CH_4+ O_2 \Rightarrow CO_2 + H_2O

Balancing the Hydrogen atoms on the right side,

\sf CH_4+ O_2 \Rightarrow CO_2 +2 H_2O

Balancing the Oxygen atoms on the left side,

\sf CH_4+ 2O_2 \Rightarrow CO_2 +2 H_2O

\rule[225]{225}{2}

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3 years ago
Please Help, will give 30 points! The following data was collected when a reaction was performed experimentally in the laborator
Sedaia [141]

Answer:

9 moles of NaNO3.

Explanation:

The balanced equation for the reaction is given below:

Al(NO3)3 + 3NaCl —> 3NaNO3 + AlCl3

Next, we shall determine the number of mole of Al(NO3)3 and NaCl that reacted and the number of mole of NaNO3 produced from the balanced equation.

From the balanced equation above,

1 mole of Al(NO3)3 reacted with 3 moles of NaCl to produce 3 moles of NaNO3.

Next, we shall determine the limiting reactant.

The limiting reactant can be obtained as follow:

From the balanced equation above,

1 mole of Al(NO3)3 reacted with 3 moles of NaCl.

Therefore, 4 moles of Al(NO3)3 will react with = (4 x 3)/1 = 12 moles of NaCl.

From the calculations made above, we can see that it will take a higher amount i.e 12 moles than what was given i.e 9 moles of NaCl to react completely with 4 moles of Al(NO3)3.

Therefore, NaCl is the limiting reactant and Al(NO3)3 is the excess reactant.

Finally, we shall determine the maximum amount of NaNO3 produced from the reaction.

In this case, the limiting reactant will be used as it will produce the maximum amount of NaNO3 since all of it is consumed by the reaction.

The limit reactant is NaCl and the maximum amount of NaNO3 produced can be obtained as follow:

From the balanced equation above,

3 moles of NaCl reacted to produce 3 moles of NaNO3.

Therefore, 9 moles of NaCl will also react to produce 9 moles of NaNO3.

From the calculations made above, the maximum amount of NaNO3 produced is 9 moles

6 0
3 years ago
An ion has 14 neutrons, 10 electrons, and a mass number of 27 what element
nasty-shy [4]

The ion is Al³⁺

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4 0
3 years ago
Consider the following reaction at constant pressure. Use the information provided below to determine the value of ΔS at 473 K.
Elis [28]

Answer:

The reaction will be spontaneous

Explanation:

To determine if the reaction will be spontaneous or not at this temperature, we need to calculate the Gibbs's energy using the following formula:

\Delta G= \Delta H - T * \Delta S

<u>If the Gibbs's energy is negative, the reaction will be spontaneous, but if it's positive it will not.</u>

Calculating the \Delta G= -1267 - 473 K* \Delta S :

\Delta G= -1267 - 473 K* \Delta S

Now, other factor we need to determine is the sign of the S variation. When talking about gases, the more moles you have in your system the more enthropic it is.

In this reaction you go from 7 moles to 8 moles of gas, so you can say that you are going from one enthropy to another higher than the first one. This results in: \Delta S>0[/tex}Back to this expression: [tex]\Delta G= -1267 - 473 K* \Delta S

If the variation of S is positive, the Gibbs's energy will be negative always and the reaction will be spontaneous.

4 0
4 years ago
(please, I need some help)
olga55 [171]
c) the salt solubility decreases with temperature.

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7 0
3 years ago
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