Answer:
Phosphagen provides the needed energy for the muscle tissues which can not be immediately supplied by glycolysis or oxidative phosphorylation. They supply immediate but limited energy as sudden demands for lots of energy by the muscle tissues arise.
Explanation:
Phosphagens are high energy storage compounds majorly found in muscular tissue of animals.
They allow maintenance of the high energy phosphate stores in its normal concentration ranges which discard the problems associated with ATP-consuming reactions in these tissues as against the presence of adenosine triphosphate.
The muscle tissues are actively working and need constant supply of energy and the energy produced by glycolysis and oxidative phosphorylation might not sum up to the needs of the tissues. So therefore, phosphagens serve as a stand by mechanism for energy production for the tissues mostly during sustained muscle activity.
The man, the muscle cells' phosphocreatinine concentration is more than three times the concentration of ATP and represent a ready reserve of high energy phosphate that can be donated directly to Adenosine diphosohate to release energy.
Different organisms use different biomolecule as a phosphagen. Majority of animals use arginine as their phosphagen, chordates use creatinine, annelids use lombricine.
They all perform these similar functions described above.
Answer:
a. 92.4%
Explanation:
Based on the reaction:
2Na₃(CO₃)(HCO₃)·2H₂O(s) → 3Na₂CO₃(s) + CO₂(g) + 5H₂O(g)
To obtain the percent yield you need to obtain moles of trona and calculate thoeretical moles of Na₂CO₃, and the ratio of obtained moles / theoretical moles of Na₂CO₃ give percent yield, thus:
Moles of trona:
1.00 metric ton × (1x10³kg / 1 metric ton) × ( 1000moles /226.03 kg) = <em>4424 moles</em>
The theoretical moles of Na₂CO₃ that produce 4424 moles of trona are (Based on the reaction, 2 moles of trona produce 3 moles of Na₂CO₃):
4424 moles trona × (3 moles Na₂CO₃ / 2 moles trona) = <em>6636 moles of Na₂CO₃.</em>
The obtained moles of Na₂CO₃:
0.650 metric ton × (1x10³kg / 1 metric ton) × (1000 moles / 105.99kg) = <em>6133 moles</em>
The ratio of obtained moles / theoretical moles gives:
6133 moles / 6636 moles = 0.924 = <em>92.4%</em>
I hope it helps!
Answer: The answer can be found on CHEG
Explanation:
Lets let our mass equal 3 on alletals and solve using d=m/v equation
Aluminum
V=3/2.70=1.11
Silver
V=3/10.5=.286
Rhenium
V=3/20.8=.144
Nickel
V=3/8.90=.337
This gives us the following list from largest to smallest Aluminum, Nickel, Silver, and Rhenium
