At&t because it costs let than Verizon and still gives you the ability to make 50 calls per week.
Here’s your answer lemme know if it’s not clear
Answer: (2.54,6.86)
Step-by-step explanation:
Given : A random sample of 10 parking meters in a beach community showed the following incomes for a day.
We assume the incomes are normally distributed.
Mean income : 
Standard deviation : 


The confidence interval for the population mean (for sample size <30) is given by :-

Given significance level : 
Critical value : 
We assume that the population is normally distributed.
Now, the 95% confidence interval for the true mean will be :-

Hence, 95% confidence interval for the true mean= (2.54,6.86)
Answer:
Midpoint is
Step-by-step explanation:
A line segment refers to line that has two endpoints.
Let
be the endpoints of a line segment.
Midpoint of the line segment is given by 
Take the given points as follows:

Midpoint of a line segment 

Answer:
x=3
Step-by-step explanation: