$36,716×4.5%×6 years =

Point A is at (-6,8) and point B is at (6, -7).<br> What is the midpoint of line segment AB?

Vsevolod [243]

The midpoint between the two points are (0,1/2)

3 0

3 years ago

What is the value of AAA when we rewrite 2^{x-6}+2^{x}2 x−6 +2 x 2, start superscript, x, minus, 6, end superscript, plus, 2, st

Nuetrik [128]

Answer:

$A=\frac{65}{64}\ or\ A=1.015625$

Step-by-step explanation:

Given:

The expression is given as:

$2^{x-6}+2^{x}$

The equivalent expression to the above expression is given as:

$A\cdot 2^{x}$

Now, simplifying the original expression using the law of indices:

$a^{m-n}=\frac{a^m}{a^n}$

So, $2^{x-6}=\frac{2^x}{2^6}$ . The expression becomes:

$=\frac{2^x}{2^6}+2^x$

Now, $2^x$ is a common factor to both the terms, so we factor it out. This gives,

$=2^x(\dfrac{1}{2^6}+1)\\\\=2^x(\frac{1}{64}+1)\\\\=2^x(\frac{1}{64}+\frac{64}{64})\\\\=2^x(\frac{1+64}{64})\\\\=2^x(\frac{65}{64})\\\\=(\frac{65}{64})\cdot 2^x$

Now, on comparing the simplified form with the equivalent expression, we conclude:

$A\cdot2^x=(\frac{65}{64})\cdot 2^x\\\\A=\frac{65}{64}\ or\ 1.015625$

Therefore, the value of 'A' is $A=\frac{65}{64}\ or\ A=1.015625$

7 0

3 years ago

Read 2 more answers

2. Tom bought 500 shares of a company’s stock for $11.06/share. He pays a broker a commission of $12 to buy and sell stock. Afte

goldfiish [28.3K]

Step-by-step explanation:

a.)Buying: total cost

Total cost= commission + (price per share× Number of of shares ) ;

Total cost= 10 + (11.06×500)=$5540

b.)Net gain or loss;

First, find cash received from sale of stock and deduct commission;

Cash from sale =10×500= $ 5000

deduct commission= 5000-10= $4990

Gain or loss= sale-cost = 4990-5540 = -$550, meaning there is a loss.

c.) Annual rate of return= (net gain or loss/amount paid)×100%

return= -550/(5540)×100 = -9.92%

3 0

3 years ago

the mean monthly rent for a sample of studio apartments in one city is $1260 with a standard deviation of $230. the monthly rent

il63 [147K]

Answer:

$1743, $1973, $1789 and $685 are unusual data values. $1973 is very unusual data value.

Step-by-step explanation:

The data values will be unusual if the data values more than 2 standard deviations away from mean.

mean=1260

standard deviation=230

mean-2*standard deviation

1260-2*230

800

mean+2*standard deviation

1720

mean±2*standard deviation=(800,1720)

The values that don't lie in this interval will be unusual.

mean-3*standard deviation

1260-3*230

570

mean+3*standard deviation

1260+3*230

1950

mean±3*standard deviation=(570,1950)

The values that don't lie in this interval will be very unusual.

$1099 lies in the interval mean±2*standard deviation and so it is within the two standard deviation away from mean. So, $1099 is not unusual.

$1651 lies in the interval mean±2*standard deviation and so it is within the two standard deviation away from mean. So, $1651 is not unusual.

$1743 don't lie in the interval mean±2*standard deviation and so it is more than the two standard deviation away from mean. So, $1743 is unusual.

$1973 don't lie in the interval mean±2*standard deviation and so it is more than the two standard deviation away from mean. So, $1973 is unusual. Also, $1973 don't lie in the interval mean±3*standard deviation and so it is more than the three standard deviation away from mean. So, $1973 is very unusual.

$846 lies in the interval mean±2*standard deviation and so it is within the two standard deviation away from mean. So, $846 is not unusual.

$1789 don't lie in the interval mean±2*standard deviation and so it is more than the two standard deviation away from mean. So, $1789 is unusual.

$1398 lies in the interval mean±2*standard deviation and so it is within the two standard deviation away from mean. So, $1398 is not unusual.

$685 don't lie in the interval mean±2*standard deviation and so it is more than the two standard deviation away from mean. So, $685 is unusual.

5 0

4 years ago

SAT scores (out of 1600) are distributed normally with a mean of 1100 and a standard deviation of 200. Suppose a school council

lys-0071 [83]

I think the answer would be c

6 0

3 years ago