Answer:
(29.46 mm, 29.54 mm).
Step-by-step explanation:
We have the standard deviation for the sample, so we use the t-distribution to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 43 - 1 = 42
95% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 42 degrees of freedom(y-axis) and a confidence level of 
. So we have T = 2.018
The margin of error is:
In which s is the standard deviation of the sample and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 29.5 mm - 0.04mm = 29.46 mm
The upper end of the interval is the sample mean added to M. So it is 29.5 mm + 0.04mm = 29.54 mm
The 95% confidence level for the true mean width is: (29.46 mm, 29.54 mm).
For this we must use foil and multiply
4*6
4*-5i
-i*6
-i*-5i
to get (respectively to above)
24
-20i
-6i
5i^2
combine all of those to get:
24-26i+5i^2
now, i squared is equal to -1, so we can simplify the above even further:
24-26i+5(-1)
24-26i-5
19-26i
Now, that would be your final answer. But if you want it in radical form you would get this: (just so you know, i is the square root of -1, or an imaginary number)
It is 4 if you see in the bottom part the line stops at -4 that's why hope it helps
Ok so when you toss a coin in the air there are many factors (wind, dimensions of the coin rotational velocity etc.) which can affect the probability of coin to be heads or tails (1/2) and it can become biased.
So a fair coin is an ideal coin which gives a perfect 50:50 (1/2) outcome for heads or tails unbiased of any factor.
She can have 10 people attend.
The room costs $50 dollars, so she has $50 left to spend on food costs.
$50/5 = 10 people
