Ask question

Ask question

All categories

3 years ago

9

Using only the values given in the table for the function, f(x) = x3 – 3x – 2, what is the interval of x-values over which the f

unction is decreasing?
(–4, 1)
(–4, –1)
(–1,1)
(–1, 2)

1 answer:

oee [108]3 years ago

6 0

Answer:(-1.1)

Step-by-step explanation:

You might be interested in

Please I need help. I need this ASAP, the screenshot is right below here.

Delicious77 [7]

Answer:

no idea

Step-by-step explanation:

no idea jsbdkanxlanvsksnsp

6 0

3 years ago

Rewrite the radical exponent as a radical

shepuryov [24]

$\bf a^{\frac{ n}{ m}} \implies \sqrt[ m]{a^ n} 
\qquad \qquad
\sqrt[ m]{a^ n}\implies a^{\frac{ n}{ m}}\\\\
-------------------------------\\\\
\left( 5^{\frac{3}{4}} \right)^{\frac{2}{3}}\implies 5^{\frac{3}{4}\cdot \frac{2}{3}}\implies 5^{\frac{1}{2}}\implies \sqrt[2]{5^1}\implies \sqrt{5}$

3 0

3 years ago

A random sample of 20 purchases showed the sample mean of $48.77 and the sample standard deviation s is $17.58. How large is the

laila [671]

Answer:

<h2>$5.03</h2>

Step-by-step explanation:

Given data

Sample Mean (M): $48.77

Sample Size (n): 20

Standard Deviation (σ) : $17.58

Confidence Level: 80%

we know that z*-Values for 80% Confidence Levels is 1.28

the expression for margin of error is given bellow\

MOE= z*σ/√n

We can now substitute into the expression and solve for the MOE as

MOE= 1.28*17.58/√20

MOE= 22.502/4.47

MOE= 22.502/4.47

MOE= 5.03

The margin of error for a 80 % confidence interval is $5.03

3 0

4 years ago

What property is y(x+5)

Nitella [24]

Disturptive property

3 0

3 years ago

A golfer hit a golf ball from a tee box that is 6 yards above the ground. The graph shows the height in yards of the golf ball a

Vaselesa [24]

Answer: C. 0 ≤ x ≤ 230

4 0

3 years ago