Answer:
2
Step-by-step explanation:
11 and 23
The solutions appear to be
{π/2, 2π/3, 4π/3}.
_____
Replacing sin(2x) with 2sin(x)cos(x), you have
2sin(x)cos(x) +sin(x) -2cos(x) -1 = 0
sin(x)(2cos(x) +1) -(2cos(x) +1) = 0 . . . . factor by grouping
(sin(x) -1)(2cos(x) +1) = 0
This has solutions
sin(x) = 1
x = π/2and
2cos(x) = -1
cos(x) = -1/2
x = {2π/3, 4π/3}
Answer: the first one is the answer I think
Step-by-step explanation:
D is the only one that could be a triangle. The way to know this is because you need to add the smallest side numbers of the triangle and it must be greater than the biggest side of the triangle. Please mark me brainliest
Answer:
+
Step-by-step explanation: