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Rus_ich [418]
3 years ago
7

6. Lars walks his dog 4 times farther than Michelle

Mathematics
1 answer:
Kobotan [32]3 years ago
7 0

Answer:

0.92

Step-by-step explanation:

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Which of the following ratios is used in finding the sine of an angle in a right triangle?
stira [4]
The ratio is called the Opposite leg or also known as Hypotenuse. Usually, in a right angle, the size of the one angle is 90 degrees while the other which is less than 90 degrees is called the hypotenuse. It is the opposite side of the angle measured 90 degrees
3 0
3 years ago
I NEED HELP!! please show all work
PtichkaEL [24]

Take the logarithm of both sides. The base of the logarithm doesn't matter.

4^{5x} = 3^{x-2}

\implies \log 4^{5x} = \log 3^{x-2}

Drop the exponents:

\implies 5x \log 4 = (x-2) \log 3

Expand the right side:

\implies 5x \log 4 = x \log 3 - 2 \log 3

Move the terms containing <em>x</em> to the left side and factor out <em>x</em> :

\implies 5x \log 4 - x \log 3 = - 2 \log 3

\implies x (5 \log 4 - \log 3) = - 2 \log 3

Solve for <em>x</em> by dividing boths ides by 5 log(4) - log(3) :

\implies \boxed{x = -\dfrac{ 2 \log 3 }{ 5 \log 4 - \log 3 }}

You can stop there, or continue simplifying the solution by using properties of logarithms:

\implies x = -\dfrac{ \log 3^2 }{ \log 4^5 - \log 3 }

\implies x = -\dfrac{ \log 9 }{ \log 1024 - \log 3 }

\implies \boxed{x = -\dfrac{ \log 9 }{ \log \frac{1024}3 }}

You can condense the solution further using the change-of-base identity,

\implies \boxed{x = -\log_{\frac{1024}3}9}

5 0
2 years ago
Someone please help math question?ASAP
natali 33 [55]
A I am pretty sure. I apologize if I am incorrect. 
3 0
3 years ago
Kareem buys candy that costs $4 per pound. He will spend at most $48 on candy. What are the possible numbers of pounds he will b
lesantik [10]

Answer:

12 lbs

Step-by-step explanation:

48/4 =12

5 0
3 years ago
Read 2 more answers
How do you write 75% as a unreduced fraction
GarryVolchara [31]

Answer:75/100

Step-by-step explanation:

75%=75/100

8 0
3 years ago
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