You have to pick at least one even factor from the set to make an even product.
There are 3 even numbers to choose from, and we can pick up to 3 additional odd numbers.
For example, if we pick out 1 even number and 2 odd numbers, this can be done in
ways. If we pick out 3 even numbers and 0 odd numbers, this can be done in
way.
The total count is then the sum of all possible selections with at least 1 even number and between 0 and 3 odd numbers.
where we use the binomial identity
Answer:
165 combinations possible
Step-by-step explanation:
This is a combination problem as opposed to a permutation, because the order in which we fill these positions is not important. We are merely looking for how many ways each of these 11 people can be rearranged and matched up with different candidates, each in a different position each time. The formula can be filled in as follows:
₁₁C₃ =
which simplifies to
₁₁C₃ =
The factorial of 8 will cancel out in the numerator and the denominator, leaving you with
₁₁C₃ =
which is 165
Answer:
option A
-2x + 4y = 4
-3x + 6y = 6
Step-by-step explanation:
In option A, if the student multiply the first equation by 3 and the second equation by -2, then the equations become
-6x+12y = 12 and
6x-12y =-12
If she adds both equations, she will get 0 = 0
This means that the system has infinite number of solutions.
Hence, the student could have started with equations -2x + 4y = 4 and -3x + 6y = 6.
Answer:
6 people
Step-by-step explanation:
If you look for the dot that has 16 balloons, you will see that it is right under 6 people