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WARRIOR [948]
2 years ago
15

Determine the domain and range of the following relation. x + 2 = [y]

Mathematics
1 answer:
AleksandrR [38]2 years ago
4 0

Answer:

Domain: all real numbers

Range: all real numbers

Step-by-step explanation:

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Express 14/6 as a mixed number in simplest form
motikmotik
I think the answer is 2 1/3 
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2 years ago
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-16.68 + 1.8s + 2.2 = 3s - 6.4
zlopas [31]

Answer:

s = -6.7

Step-by-step explanation:

- 16.68 + 1.8s + 2.2 = 3s - 6.4

- 16.68 + 2.2 + 1.8s = 3s - 6.4

- 14.48 + 1.8s = 3s - 6.4

Collect like terms

Note: crossing over equals to, the sign will change

Hint: either from

- to +

Or

+ to -

-14.48 + 6.4 = 3s - 1.8s

-8.08 = 3s - 1.8s

-8.08 = 1.2s

Divide both sides by 1.2, to get the value of s

-8.08/1.2 = 1.2s/1.2

-6.7 = s

s = -6.7

3 0
3 years ago
Solve each quadratic equation by factoring and using the zero product property.
Iteru [2.4K]

Answer:

x=5                            x=6

Step-by-step explanation:

x^2 - 8x + 30 = 3x

Subtract 3x from each side

x^2 - 8x-3x + 30 = 3x-3x

x^2 - 11x + 30 = 0

What 2 numbers multiply to 30 and add to -11

-5*-6 = 30

-5+-6 = -11

(x-5) (x-6) =0

Using the zero product property

x-5 = 0  and x-6 =0

x-5+5 =0+5   and x-6+6 =0+6

x=5                            x=6

7 0
3 years ago
Read 2 more answers
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ANTONII [103]

Answer:

sin B sin C. When this equation is combined with the previous equation, we obtain the Law of. Sines. ... ас. B. FIGURE 4.5 Solving an. ASA triangle. Keep in mind that we must be given one of the three ratios to apply the ...

6 0
3 years ago
Paaaa hellllpppp po with solution po sana​
ira [324]
<h2>Solving Equations</h2>

To solve linear equations, we must perform inverse operations on both sides of the equal sign to <em>cancel values out</em>.

  • If something is being added to x, subtract it from both sides.
  • If something is being subtracted from x, add it on both sides.
  • Same with multiplication and division. If x is being divided, multiply. If x is being multiplied, divide.

We perform inverse operations to<em> combine like terms</em>. This means to get x to one side and everything else on the other.

<h2>Solving the Questions</h2><h3>Question 1</h3>

5x+7=15

Because 7 is being added to x, subtract it from both sides:

5x+7-7=15-7\\5x=8

Because x is being multiplied by 5, divide both sides by 5:

\dfrac{5x}{5}=\dfrac{8}{5}\\\\x=\dfrac{8}{5}

Therefore. x=\dfrac{8}{5}.

<h3>Question 2</h3>

7x+4=5x-18

Here, we can group all the x values on the left side of the equation. Subtract 5x from both sides:

7x+4-5x=5x-18-5x\\2x+4=-18

To isolate x, subtract 4 from both sides:

2x+4-4=-18-4\\2x=-22

Divide both sides by 2:

\dfrac{2x}{2}=\dfrac{-22}{2}\\\\x=-11

Therefore, x=-11.

6 0
2 years ago
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