<span>4[(10-4) 2 to the second power divided by 4]
=4x6x2</span> to the second power divided by 4
=6x2 to the second power
=6x4
=24
Hope that helps and hope that I didn't misunderstand your question
The probability of one head and one tail is 2/3.
<u>Step-by-step explanation</u>:
- The possibilities for flipping two fair coins are {T,T}, {H,H}, {H,T}, {T,H}
- Given the case that at least one coin lands on a head, So the total possibilities are {H,H}, {H,T}, {T,H} = 3 possibilities
- Required event is 1 head and 1 tail= {H,T}, {T,H} = 2 possibilities
To calculate the probability of one head and one tail,
Probability = required events / Total events
Probability = 2/3
The slope is m=7/10
I hope it helps :)
2^x = 32
x = 5
Hope this helps!
Answer:
srat
Step-by-step explanation:hehe i really dont know
