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Lilit [14]
3 years ago
5

Why do translations produce parallel lines

Mathematics
1 answer:
pav-90 [236]3 years ago
7 0

Answer:The distance between the lines stays constant, and they never intersect. In other words, you can translate (move) either line by that constant distance, in some direction, to get the other line. It's just like how when you change the y-intercept but keep the slope the same, you get parallel lines.

Step-by-step explanation:

Hope this helps ツ

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THE X-INTERCEPT OF THE LINE X=3.5 IS
tiny-mole [99]
Well.. for the equation x= 3.5, let's take a look at its values
\bf \begin{array}{lrlll}
x&y\\
\textendash\textendash\textendash\textendash\textendash\textendash&\textendash\textendash\textendash\textendash\textendash\textendash\\
3.5&-\infty\\
3.5&-1,000,000\\
3.5&-1,000\\
3.5&-100\\
3.5&-10\\
3.5&-1\\
3.5&0\\
3.5&1\\
3.5&10\\
3.5&100\\
3.5&1,000\\
3.5&1,000,000\\
3.5&1+\infty
\end{array}

so.. notice.. no matter what "y" is, "x"  will always be 3.5,
so is really just a horizontal line, thus, look at the picture below

8 0
4 years ago
20 POINTS! Please help
Marysya12 [62]

The complete square will be  (x-3)^{2} = 3

Step-by-step explanation:

Given,

2x^{2} -12x+12=0

or, x^{2} -6x+6=0 [ by eliminating 2 from both the sides]

To make it square

x^{2} -6x+6=0

or, x^{2} -2xX3+9-9+6=0 [ (a+b)^{2}=a^{2} +2ab+b^{2}

or, (x-3)^{2} = 9-6

or, (x-3)^{2} = 3

Hence the correct option is B

3 0
4 years ago
What is the area of the composite figure?
german

Answer:

16 + 6pi cm

Step-by-step explanation:

We have a square of length 4 cm

A = s^2 = 4^2 = 16

We have 3 semi circles

with radius 2

A semi circle has an area of

1/2 pi r^2 = 1/2 pi (2)^2 = 1/2 (4pi) = 2pi

There are 3 of them

3 * 2 pi = 6pi

Add the areas together for the square and the semicircles

16 + 6pi

6 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20-%205%20%5Csqrt%7B49%20-%208a%20%3D%20%20-%2035%7D%20" id="TexFormula1" title=" - 5 \sqrt{4
Tcecarenko [31]

- 5 \sqrt{49 - 8a =  - 35}  \\  \\ 1. \:  - 8a = 0 \\  \\ 2. \:  \frac{ - 8a}{ - 8} =  \frac{0}{ - 8}   \\ a = 0

7 0
3 years ago
Please help!!
enot [183]

Since g(h(x))=h(g(x))= x, hence functions h and g are inverses of each other

Given the functions expressed as:

h(x) =\sqrt{2x+2}\\g(x)\frac{x^2-2}{2}  \\

In order to check whether they are inverses of each other, we need to show that h(g(x)) = g(h(x))

Get the composite function h(g(x))

h(g(x))=h(\frac{x^2-2}{2} )\\h(g(x))=\sqrt{2(\frac{x^2-2}{2} )+2}\\h(g(x))=\sqrt{x^2-2+2} \\h(g(x))=\sqrt{x^2}\\h(g(x))=x

Get the composite function g(h(x))

g(h(x))=\frac{(\sqrt{2x+2} )^2-2}{2} \\g(h(x))=\frac{2x+2-2}{2}\\g(h(x))=\frac{2x}{2}\\g(h(x))=x

Since g(h(x))=h(g(x))= x, hence functions h and g are inverses of each other

Learn more on inverse functions here; brainly.com/question/14391067

7 0
3 years ago
Read 2 more answers
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