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3 years ago

An expression is given

Mathematics

2 answers:

vovangra [49]3 years ago

8 0

Step-by-step explanation:

The coefficients are 4, 5 and 7

There is no constant

The second one is right

mojhsa [17]3 years ago

4 0

Answer:

Coefficient: 4,5,7 and Constant: None

Step-by-step explanation:

A coefficient can be defined as the number next to the variable or unknown numbers

This would be 4, 5, and 7

However, there does not seem to be a constant, which is a value that should not be the coefficient of a variable.

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Please help brainiest is award.

lesantik [10]

it's easier b or d I'm not sure

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3 years ago

Read 2 more answers

Solve for x <br> 0.7x=340

RSB [31]

<h2>Hello There, today we will be solving your problem</h2>

$\huge\red{\mid{\underline{\overline{\textbf{EQUATION AND ANSWER}}}\mid}}$

_________________

Let's solve this equation using simple algebra,

<h2>_________________</h2><h2>Definitions </h2>

Algebra<em> - Algebra is one of the broad areas of mathematics. Roughly speaking, algebra is the study of mathematical symbols and the rules for manipulating these symbols in formulas; it is a unifying thread of almost all mathematics</em>

Division <em>- Division, otherwise known as the inverse of multiplication separates a certain number into what it has been divided by.</em>

_________________

Now that we understand the definition we can further solve this equation

$\large\red{\mid{\underline{\overline{\textbf{Values}}}\mid}}$

$0.7x$
$340$

________________

Now we will add to solve this equation

$\large\red{\mid{\underline{\overline{\textbf{Equtation}}}\mid}}$

$0.7x=340$

-Use simple division

$x=485.714286$

This is repeating*

$\large\red{\mid{\underline{\overline{\textbf{Answer}}}\mid}}$

$0.7x=340$

The answer is $x=485.714286$ repeating

6 0

1 year ago

Find a linear approximation of the function f(x)=\sqrt[3]{1+x} at a=0, and use it to approximate the numbers \sqrt[3]{.96} and \

34kurt

$f(x)=\sqrt[3]{1+x}=(1+x)^{1/3}\implies f'(x)=\dfrac1{3(1+x)^{2/3}}$

The linear approximation to $f(x)$ around $x=a$ is then

$L(x)=f(a)+f'(a)(x-a)\approx f(x)$

So the approximation centered at $a=0$ will be

$L(x)=f(0)+f'(0)x=(1+0)^{1/3}+\dfrac x{3(1+0)^{2/3}}$
$L(x)=1+\dfrac x3$

which means we have

$\sqrt[3]{0.96}\approx L(0.96)=1+\dfrac{0.96}3=1.32$

$\sqrt[3]{1.02}\approx L(1.02)=1+\dfrac{1.02}3=1.34$

Compare to the actual values of

$\sqrt[3]{0.96}\approx0.9864$

$\sqrt[3]{1.02}\approx1.0066$

4 0

3 years ago

When working out on the track, Sean normally averages x laps per minute, while Jill averages y laps

Shalnov [3]

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4 years ago

What are the the values of x and y that satisfy this equation?

neonofarm [45]

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3 years ago