Answer:
The minimum sample size we should anticipate using is 601.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of , and a confidence level of , we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of .
The margin of error is:
We have no history with this characteristic, so we have no idea as to what the proportion might be.
This means that we use , which is when the largest sample size will be needed.
95% confidence level
So , z is the value of Z that has a pvalue of , so .
What is the minimum sample size we should anticipate using?
This is n for which M = 0.04. So
Rounding up, 601
The minimum sample size we should anticipate using is 601.
Answer:
x=7
y=-5
Step-by-step explanation:
that is the answer
3 2/3 x # = 2/9
# = 2/9 \ 3 2/3
# = 2/33 or 0.067
Answer: 28
Step-by-step explanation:
2 × 8 = 16
8 + 4 = 12
12 ÷ 2 = 6
6 × 2 = 12
16 + 12 = 28